Light with wavelength i passes through a narrow slit of width w and is seen on a screen which is located at a distance D in front of the slit. The first minimum of the diffraction pattern is at distance d from the middle of the central maximum. Calculate the wavelength of light if D=1.2 m, d=1 mm and w = VAD. Give your answer in nanometers.

Please explain each step....You shine monochromatic light with wavelength 720 nm through a slit that has a width of 0.750 mm and observe a diffraction pattern on a screen that is 3.60 m from the slit. The intensity at the center of the central maximum is Io = 7.80 W/m2. What is the intensity of the light at a point on the pattern that is halfway between the center of the central maximum and the first minimum of interference? The purple line in the figure shows the points that are halfway between the center of the central max. and the first min.

The width of the central peak in a single-slit diffraction pattern is 5.0 mm. The wavelength of the light is 600. nm, and the screen is 1.9 m from the slit. (a.) What is the width of the slit in microns? (D= ?)  (b.) What is the ratio of the intensity at 4.2mm from the center of the pattern to the intensity at the center of the pattern? (I/I0= ?)

One way to determine the index of refraction of a gas is to use an interferometer. As shown below, one of the beams of an interferometer passes through a glass container that has a length of L = 1.8 cm. Initially the glass container is a vacuum. When gas is slowly allowed into the container, a total of 7571 dark fringes move past the reference line. The laser has a wavelength of 687 nm (this is the wavelength when the light from the laser is moving through a vacuum). Laser Mirror Glass Container Beam Splitter Diffraction Pattern Mirror A.) Determine how many wavelengths will fit into the glass container when it is a vacuum. Since the light passes through the container twice, you need to determine how many wavelengths will fit into a glass container that has a length of 2L. number of wavelengths (vacuum) = B.) The number of dark fringes is the difference between the number of wavelengths that fit in the container (length of 2L) when it has gas and the number of wavelengths that fit in…

Problem 6: We use 633-nm light from a He-Ne laser to demonstrate Young's double-slit experiment. The interference pattern will be projected on a wall that is 5.0 m from the slits. We want the distance between the m=0 and m=1 maxima to be 25 cm. What slit separation is required to produce the desired interference pattern?

You illuminate a slit with a width of 78.1 µm with a light of wavelength 729 nm and observe the resulting diffraction pattern on a screen that is situated 2.27 m from the slit. What is the width w, in centimeters, of the pattern's central maximum? W = cm

An electric current through an unknown gas produces several distinct wavelengths of visible light. Consider the first order maxima for the wavelengths 403 nm, 428 nm, 511 nm, and 682 nm of this unknown spectrum, when projected with a diffraction grating of 5,000 lines per centimeter.Randomized Variablesλ1 = 403 nmλ2 = 428 nmλ3 = 511 nmλ4 = 682 nm Part (a)  What would the angle (in degrees) be for the 403 nm line?   Part (b)  What would the angle (in degrees) be for the 428 nm line?   Part (c)  What would the angle (in degrees) be for the 511 nm line?   Part (d)  What would the angle (in degrees) be for the 682 nm line?    Part (e)  Using this grating, what would be the angle (in degrees) of the second-order maximum of the 403 nm line?

Fringes in the Thomas Young experiment are produced using sodium light of wavelength 670 nm and two slits which are 1.2 mm apart. If the fringes are formed on a screen 0.8 m away from the slits, how far is the third order bright fringe from the middle of the screen? Give your answer in millimeters (mm).

The diffraction grating is a way of separating or dispersing light of different wavelengths, producing a spectrum of light.  The grating interferes light constructively in particular directions: dsinθm=mλdsin⁡θm=mλ  For a particular angle, we calculate the wavelength. The grating constant (or line density) is 500 lines per mm -- every millimeter has 500 lines scratched onto it, equally spaced.  The quantity d is the distance between the lines, and λ is the light wavelength.   In the previous problem, calculate y2, where one of the second-order spots appears on the meter stick.  Either that, or show that y2 can't be determined.

Light with wavelength A passes through a narrow slit of width w and is seen on a screen which is located at a distance D in front of the slit. The first minimum of the diffraction pattern is at distance d from the middle of the central maximum. Calculate the wavelength of light if D=2.3 m, d=1 mm and w = VAD. Give your answer in nanometers. Answer: Choose... +