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One way to determine the index of refraction of a gas is to use an interferometer. As shown below, one of the beams of an interferometer passes through a glass container that has a length of L = 1.8 cm. Initially the glass container is a vacuum. When gas is slowly allowed into the container, a total of 6894 dark fringes move past the reference line. The laser has a wavelength of 635 nm (this is the
A.) Determine how many wavelengths will fit into the glass container when it is a vacuum. Since the light passes through the container twice, you need to determine how many wavelengths will fit into a glass container that has a length of 2L.
number of wavelengths (vacuum) =
B.) The number of dark fringes is the difference between the number of wavelengths that fit in the container (length of 2L) when it has gas and the number of wavelengths that fit in the container (length of 2L) when it is a vacuum. Use this knowledge to determine how many wavelengths fit into the container (length of 2L) when it is finished being filled with gas.
number of wavelengths (gas) =
C.) Determine the index of refraction of the gas at its final density. How can you combine your answers for (A) & (B) to take advantage of the formula derived in the Content section?
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- A coating is being applied to reduce the reflectivity of a pane of glass to light with a frequency of 4.14 × 10¹4 Hz that is incident normally on the pane. If the material has an index of refraction of 1.34 and the glass has an index of refraction of 1.537, what is the minimum thickness the coating should have in nanometers? Please keep one decimal place in your answer. (c = 3.00 × 108 m/s)arrow_forwardA beam of light of wavelength 691 nm passes through two closely spaced glass plates, as shown in the figure.For what minimum nonzero value of the plate separation d will the transmitted light be bright? (This arrangement is often used to measure the wavelength of light and is called a Fabry-Perot interferometer.)arrow_forward
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