Six message signals each of bandwidth 5 kHz are time division multiplexed and transmitted. Determine the signaling rate and the minimum channel bandwidth of the PAM/TDM channel.?
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Six message signals each of bandwidth 5 kHz are time division multiplexed and transmitted. Determine the signaling rate and the minimum channel bandwidth of the PAM/TDM channel.?
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- Draw the TDM signal with 2 signals being multiplexed over the channel?1) Compared to AM, frequency modulation (FM) is known for it's: a. efficient bandwidth utilization. b. efficient noise cancellation. c. efficient against channel non-linearity. d. both b and c.be 5.88 Six message signals each of bandwidth 5 kHz are time division multiples and transmitted. Determine the signaling rate and the minimum channel bandwidth oft PAM/TDM channel.
- Fora standard SSBSC carrier AM, the peak unmodulated carrier peak voltage is 10 V for a load resistance of 10 ohms and modulation index of 1. What will be the total transmitted power?4. What parameter of a PPM signal varies in direct proportion to the message signal amplitude? a. the average frequency of the PPM pulses b. the distance between the PPM pulses c. the amplitude of the PPM pulses d. the width of the PPM pulses 5. What is the function of the prefilter in a PTM modulation circuit? completely removes frequencies greater than 8 kHz a. completely removes the PTM signal's first replica b. frequencies c. filters the message signal d. partially reconstructs and amplifies the message signal 6. What advantage does a PPM signal have over a PWM signal? a. can be used for message signals greater than 5 kHz b. requires lower sampling frequency c. easier to demodulate d. requires less transmission power 7. Why does PTM require a higher sampling frequency than PAM? a. The amplitude of PTM signals is constant. b. There are more sidebands in the first replica of a PTM c. Signal than in a PAM signal. d. A sample/hold circuit requires a higher sampling frequency. e. There…Question 5: a) In the context of WCDMA, answer the following questions: What is the chip rate of WCDMA? i. ii. What is the duration for WCDMA frame? iii. For the figure shown below, what is the spreading factor? Symbol iv. V. vi. vii. Data Spreading code Spread signal Datax code Spreading What is the corresponding processing gain? For the figure shown below, what is the multiplexing mode used? Uplink Downlink Frequency Time WCDMA has a frequency reuse of 1 between different cells. What does that mean? If fast fading occurs when the path difference between two received signals is half wavelength. Calculate the path difference at a frequency equals to 2 GHz.
- 3. Explain disadvantages of ASK modulation system.2. (a) Answer the following questions in more than two lines. i) What type of signals do a WDM use? ii) When to use WDM and what is the main component used in it to do the multiplexing and demultiplexing? iii) Can a TDM multiplex the type of signals used in a WDM? Explain your answer in one line.Explain the relationship between bits per second and baud for an FSK system. Define the following terms for FSK modulation: frequency deviation, modulation index, and deviation ratio. Explain the relationship between (a) the minimum bandwidth required for an FSK system and the bit rate and (b) the mark and space frequencies.
- 5. What is the function of the prefilter in a PTM modulation circuit? completely removes frequencies greater than 8 kHz a. completely removes the PTM signal's first replica b. frequencies c. filters the message signal d. partially reconstructs and amplifies the message signalb) An 10 bits single channel PCM system gives an output of 102 kilo bit per second(kbps). Calculate: i. The sampling frequency of the system. ii. The highest possible modulating frequency of the system. iii. The bit duration of the system. iv. The Bandwidth of the system.C- Put TRUE or FALSE for only TWO of the following and say why: 1. PCM modulation is very complex technique compared to DM. 2. Envelope detection for PSK signal is possible via using DPSK. 3. Afrequency reuse factor can be reached to "1" as a maximum value.