College Physics
11th Edition
ISBN: 9781305952300
Author: Raymond A. Serway, Chris Vuille
Publisher: Cengage Learning
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- An electron accelerates between the cathode and the anode. It passes through a potential difference of 2000 v. The charge on an electron is 1.6 × 10-19 C and the mass of an electron is 9.1 x 10-31 kg. Find the following: A. Describe what is happening to the atoms in the screen as they are hit by electrons. B. State the kinetic energy, in ev, of the electron when it hits the screen. C. Calculate the work done on the electron passing through a pd of 2000 V. Give your answer in joules. D. The work done on the electron becomes kinetic energy of the electron. Write down the formula for kinetic energy in terms of mass m and speed v. E. Using your answers to questions 3 and 4, find the speed of the electron. F. The anode is connected to the screen. State and explain what, if anything, happens to the speed of the electron as it passes from the anode to the screen. G. In 10 seconds, 6.0 × 10^17 electrons hit the screen. Calculate: (a) the charge hitting the screen in 10 seconds (the charge on…arrow_forwardAn electron moving parallel to the x axis has an initial speed of 3.7 x 106 m/s at the origin. Its speed is reduced to 1.4 x 105 m/s at x = 2 cm. Calculate the electric potential difference 1. between the origin and x -= 2 cm. 2. A proton is released from rest in a uniform electric field whose magnitude is 5000 V/m. Through what potential difference will it have passed after moving 0.25 meters? How fast will it be going after it has travelled 0.25 meters?arrow_forwardThe interior of a cell is measured to be 70mV below its surroundings. This is due to a layer of positive charge on the membrane's outer surface, and a layer of negative charge on the inner surface. The size of the separated charge is Q=1.2 x 10-13 C. What is the cell membrane's capacitance? a. 2.9x10^-3 F b. 1.7x10^-12 F c. 8.4x10^-15 F d. 5.8x10^11 Farrow_forward
- Two large aluminum plates are separated by a distance of 2.0 cm and are held at a potential difference of 195 V. An electron enters the region between them at a speed of 3.2 × 105 m/s by passing through a small hole in the negative plate and continues moving toward the positive plate. Assume the electric field between the plates is uniform. 1. What is the electron’s speed, in meters per second, when it is 0.1 cm from the negative plate? 2. What is the electron’s speed, in meters per second, when it is 0.5 cm from the negative plate? 3. What is the electron’s speed, in meters per second, when it is 1.0 cm from the negative plate? 4. What is the electron’s speed, in meters per second, when it is 1.5 cm from the negative plate? 5. What is the electron’s speed immediately before it strikes the positive plate?arrow_forwardFigure 2cm Al lem B InCarrow_forwardPart A What is the electric potential a distance of 2.8x10-15 m away from a proton? Express your answer using two significant figures. ? V: V %3D Submit Request Answer Part B What is the electric potential energy of a system that consists of two protons 2.8x10-15 m apart-as might occur inside a typical nucleus? Express your answer using two significant figures. ? PE = Jarrow_forward
- A parallel plate capacitor in air is constructed with two 13 cm x 13 cm square conductors separated by 3 mm. a) Determine the value of the capacitance of this parallel plate capacitor. b) This capacitor is placed across a 12 V battery and allowed to fully charge. What is the value of this charge? To continue, please enter your answer in b) in units of nC. Round your answer to 1 decimal place.arrow_forwardConsider the charge distribution shown in the figure. The distance d is 1.4 cm, and all the charges are equal to q=+12nC a. What is the electric potential energy of the charge configuration of the figure below? b. What is electric field and electric potential in point P?c. How does the energy of the configuration change if you put negative q=−12nC in point P.arrow_forward
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