College Physics
College Physics
11th Edition
ISBN: 9781305952300
Author: Raymond A. Serway, Chris Vuille
Publisher: Cengage Learning
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Please fill in the blanks. Suppose an electron (q equals negative e equals negative 1.6 cross times 10 to the power of negative 19 end exponent space text C end text space,m equals 9.1 cross times 10 to the power of negative 31 end exponent space text kg end text) is accelerated from rest through a potential difference of Vab = +5000 V. Solve for the final speed of the electron. Express numerical answer in two significant figures.

QUESTION 5
Suppose an electron (q = - e= -1.6 × 10¬19 c ,m=9.1 × 10¬31 kg) is accelerated from rest through a potential difference of Vab = +5000 V. Solve for the
final speed of the electron. Express numerical answer in two significant figures.
The potential energy U is related to the electron charge (-e) and potential Vab is related by the equation:
U =
Assuming all potential energy U is converted to kinetic energy K,
K+U = 0
K= -U
1
=5mv and using the formula for potential energy above, we arrive at an equation for speed:
Since K
v = (
1/2
Plugging in values, the value of the electron's speed is:
x 107 m/s
V=
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Transcribed Image Text:QUESTION 5 Suppose an electron (q = - e= -1.6 × 10¬19 c ,m=9.1 × 10¬31 kg) is accelerated from rest through a potential difference of Vab = +5000 V. Solve for the final speed of the electron. Express numerical answer in two significant figures. The potential energy U is related to the electron charge (-e) and potential Vab is related by the equation: U = Assuming all potential energy U is converted to kinetic energy K, K+U = 0 K= -U 1 =5mv and using the formula for potential energy above, we arrive at an equation for speed: Since K v = ( 1/2 Plugging in values, the value of the electron's speed is: x 107 m/s V=
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