An electron moving parallel to the x axis has an initial speed of 3.7 x 106 m/s at the origin. Its speed is reduced to 1.4 x 105 m/s at x = 2 cm. Calculate the electric potential difference 1. between the origin and x -= 2 cm. 2. A proton is released from rest in a uniform electric field whose magnitude is 5000 V/m. Through what potential difference will it have passed after moving 0.25 meters? How fast will it be going after it has travelled 0.25 meters?

14. The plates of a parallel-plate capacitor are 4.50 mm apart, and each carries a charge of magnitude 85.0 nC. The plates are in vacuum. The electric field between the plates has a magnitude of. What is the potential difference in Volts between the plates? Write the answer in whole number.

What potential difference is needed to accelerate an electron from rest to a speed of 1.2x106 m/s? Express your answer to two significant figures and include the appropriate units. μÅ AV= Value Submit Request Answer Ć Units ?

a. A potential difference of 5.00 V is placed across a 43.1 mF capacitor. How much charge is stored in the capacitor? b. In the case of part (a), how much energy is stord in the 43.1 mF capacitor with a 5.00 V potential difference across its plates?

An air-filled capacitor consists of two parallel plates, each with an area of 7.60 cm2, separated by a distance of 1.40 mm. A 15.0-V potential difference is applied to these plates. (a) Calculate the electric field between the plates. 10.7 V kV/m (b) Calculate the surface charge density. 948 There are a number of ways to get to this answer. How do you calculate the electric field due to a uniform surface charge density? nC/m2 (c) Calculate the capacitance. 4.804 V pF (d) Calculate the charge on each plate. 72.06 pC

A moving particle encounters an external electric field that decreases its kinetic energy from 9140 eV to 5710 eV as the particle moves from position A to position B. The electric potential at A is -63.0 V, and that at B is +10.0 V. Determine the charge of the particle. Include the algebraic sign (+ or -) with your answer.

Charge q is fired through a small hole in the positive plate of a capacitor, as shown.a. If q is a positive charge, does it speed up or slow down inside the capacitor? Answer this question twice: (i) Using the concept of force. (ii) Using the concept of energy.b. Repeat part a if q is a negative charge.

Two charged, parallel, flat conducting surfaces are spaced d = 0.866 cm apart and produce a potential difference AV = 760 V between them. An electron is projected from one surface directly toward the second. What is the initial speed of the electron if it stops just at the second surface? Number i Units

An electron is released from rest at the negative plate of a parallel plate capacitor and accelerates to the positive plate (see the drawing). The plates are separated by a distance of 1.7 cm, and the electric field within the capacitor has a magnitude of 2.8 x 106 V/m. What is the kinetic energy of the electron just as it reaches the positive plate? Electric field Electron KE positive + + + + + + + +

Calculate the speed of a proton that is accelerated from rest through an electric potential difference of 120 V. Calculate the speed of an electron that is accelerated through the same electric potential difference.