College Physics
11th Edition
ISBN: 9781305952300
Author: Raymond A. Serway, Chris Vuille
Publisher: Cengage Learning
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A parallel plate capacitor in air is constructed with two 32 cm x 32 cm square conductors separated by 4 mm.
a) Determine the value of the capacitance of this parallel plate capacitor.
b) This capacitor is placed across a 22 V battery and allowed to fully charge. What is the value of this charge?
To continue, please enter your answer in b) in units of nC.
Round your answer to 1 decimal place.
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- Look at the arrangement of the capacitors below. A) Find the equivalent capacitance of the arrangement. B) What is the voltage across each capacitor? V₁ = V₂ = V3 = V4= C) What is the magnitude of the charge stored on each capacitor's plates? Q₁ = Q₂ = Q3 Q4= A AV₁ = 10 volts AB 6F 4 F 6 F 4 F B Now imagine that a dielectric with dielectric constant k = 5.0000 is placed inside the upper left capacitor. D) Find the new equivalent capacitance of this arrangement. AVAB 10 volts still A k=5.0000 THE 6 F B 4F 4Farrow_forwardItem 8 Learning Goal: To review the meaning of capacitance and ways of changing the capacitance of a parallel-plate capacitor. Capacitance is one of the central concepts in electrostatics. Understanding its meaning and the difference between its definition and the ways of calculating capacitance can be challenging at first. This tutorial is meant to help you become more comfortable with capacitance. Recall the fundamental formula for capacitance: C = Q/AVC, where C is the capacitance in farads, Q is the charge stored on the plates in coulombs, and AVC is the potential difference (or voltage) between the plates. In the following problems it may help to keep in mind that the voltage is related to the strength of the electric field E and the distance between the plates, d, by AVc = Ed. Part A What property of objects is best measured by their capacitance? the ability to conduct electric current the ability to distort an external electrostatic field the ability to store charge Submit Part…arrow_forwardA parallel-plate capacitor is formed from two 2.8 cm-diameter electrodes spaced 2.6 mm apart. The electric field strength inside the capacitor is 3.0 x 10° N/C. Part A What is the magnitude of the charge (in nC) on each electrode? Express your answer in nanocoulombs. Πνα ΑΣφ ? Q = nCarrow_forward
- с A slab of copper of thickness b is thrust into a parallel-plate capacitor of plate area A and plate separation d, as shown in the figure above; the slab is exactly halfway between the plates. NOTE: Express your answers in terms of the given variables using eo and q when necessary. (a) What is the capacitance after the slab is introduced? = W b (b) If a charge q is maintained on the plates, what is the ratio of the stored energy before to that after the slab is inserted? d U₁ Uf (c) How much work is done on the slab as it is inserted? = = (d) Is the slab sucked in or must it be pushed in? [Choose one ▾arrow_forwardPart A The voltage across a 4 μF capacitor increases by 48 V. If the final charge on the capacitor is 507 μC, determine the initial charge. Q₁ = Part B Two parallel plates each have a charge magnitude of 601 nC. Between the plates is a dielectric with K = 86. Additionally, the E-field between the plates is 7.81x105 V/m. Determine the area of each plate. A= Part C A capacitor with no dielectric has an E-field of 88 kV/mm between the plates. The area of each plate is 46.3 cm² and the voltage across the capacitor is 1.5 V. Determine the capacitance. C=arrow_forwardWhat is the capacitance of a pair of circular plates with a radius of 7.0 cm separated by 2.9 mm of mica? The dielectric constant of mica is 7. Express your answer using one significant figure and include the appropriate units. µA ? C = Value Units Submit Request Answerarrow_forward
- IP A parallel-plate capacitor filled with air has plates of area 6.6x10-3³ m² and a separation of 0.36 mm. Part A Find the magnitude of the charge on each plate when the capacitor is connected to a 12-V battery. Express your answer using two significant figures. Q= Submit Part B Submit O Increase O Decrease O Stay the same 17| ΑΣΦ | Will your answer to part A increase, decrease, or stay the same if the separation between the plates is increased? Part D Request Answer Part C Complete previous part(s) Q = Submit Request Answer www. ? Calculate the magnitude of the charge on the plates if the separation is 0.83 mm. Express your answer using two significant figures. IV—| ΑΣΦ 3 Request Answer nC ? nCarrow_forwardTwo parallel 2.0-cm-diameter flat aluminum electrodes are spaced 0.50 mm apart. The electrodes are connected to a 200 V battery. Part A What is the capacitance? Express your answer with the appropriate units. Part B What is the magnitude of the charge on each electrode? Express your answer with the appropriate units.arrow_forwardA spherical capacitor consists of an inner spherical shell of radius R1 and an outer spherical shell of radius R2, as shown above. Our goal is to calculate the capacitance of this configuration of electrodes.To start, suppose the inner sphere has a charge +Q and the outer sphere an equal but opposite charge -Q. Find the capacitance using the following steps:1. Use Gauss's law to find an expression for the electric field in the region between the two spheres.2. Find an expression for the potential difference between the spheres from the electric field (you'll have to integrate the electric field from the negative electrode to the positive one).3. Calculate the capacitance from C = Q / ΔV.Suppose in this case that R1 = 2.00 cm and R2 = 4.30 cm. What is the value of the capacitance?arrow_forward
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