Situation 5 : Rotating Vessels A closed cylinder 1.0 m Ø and 2.0 m high contains water 1.5 m deep, the remaining air space being under a pressure of 120 kPa. 1. Compute the pressure at the center of the bottom if = 12 rad/s. (126 kPa) 2. Compute the pressure at the circumference of the bottom. (144 kPa) 3. What will just zero the depth of water at the center. (17.9 rad/s) 4. How much area of the bottom is not covered with water if = 20 rad/s? (0.042 m²)

Two vessels are attached to an inverted U-tube containing air at 23 psi and 70°F. If vessel A contains water that rises in the tube at 85 inches and vessel B contains glycerin, determine the difference in pressure (psf) between vessels A and B and the absolute pressure at point B (inHg). Given that the atmospheric pressure is 14.6 psia and y is 16 inches. SGycerin=1.26. B dycerin S-1.26

Two pipes A & B carries an oil of specific gravities 0.9 & 1.2 respectively.  The center of the pipe A is 30 cm above the pipe B.  The height of oil in right limb is 50 cm.  Also, the mercury level difference is found in right limb as 90 cm.  Find the pressure difference between these two pipes in kPa. Also find the pressure  equivalent in water head in mm.               The difference of pressure between two pipes (PA-PB)  (Unit is in kPa) ? Equivalent to Water head in mm ?

4. The siphon shown is 76 mm in diameter. It draws oil from a large tank. The loss of head up to the summit is 6 cm and from the summit to the exit is 23 cm of oil. a. Calculate the exit velocity. b. Calculate the pressure at the summit. 0.6 8.3 76- mm 0 siphon