Answered: Sand o' = 40° c' = 0 y = 16.5 kN/m3 1.5…

Sand o' = 40° c' = 0 y = 16.5 kN/m3 1.5 m FIGURE 6.24 A continuous foundation with load eccentricity 2 m Eq. 6.67 9ule) = qu 1-

Principles of Foundation Engineering (MindTap Course List)

9th Edition

ISBN:9781337705028

Author:Braja M. Das, Nagaratnam Sivakugan

Publisher:Braja M. Das, Nagaratnam Sivakugan

Chapter6: Shallow Foundations: Ultimate Bearing Capacity

Section: Chapter Questions

Problem 6.9P: A column foundation (Figure P6.9) is 3 m × 2 m in plan. Given: Df = 1.5 m, ф′ = 25°, c′ = 70 kN/m2....

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Load and resistance factor design

Load and resistance factors design (LRFD), also known as Limit state design (LSD), refers to the design method used in building engineering. A boundary condition is a condition of a structure where it can no longer meet the relevant design requirements. The condition may refer to the load level or other actions on the structure, while the terms refer to the integrity of the structure, suitability for use, durability, or other design requirements. A structure designed for LRFD is limited to keeping track of all possible actions during its design time and is always ready for use, with the appropriate level of reliability in each boundary condition. LRFD-based construction codes clearly define the appropriate levels of reliability in their instructions.

Question

A continuous foundation is shown in Figure 6.24. If the load eccentricity is 0.2 m, determine the ultimate load, Q_u, per unit length of the foundation. Use Meyerhof’s effective area method.

Solve this using attached equation

Sand
o' = 40°
c' = 0
y = 16.5 kN/m3
1.5 m
FIGURE 6.24 A continuous foundation with load
eccentricity
2 m
Eq. 6.67
9ule) = qu
1-

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