Principles of Foundation Engineering (MindTap Course List)
9th Edition
ISBN: 9781337705028
Author: Braja M. Das, Nagaratnam Sivakugan
Publisher: Cengage Learning
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Chapter 6, Problem 6.9P
A column foundation (Figure P6.9) is 3 m × 2 m in plan. Given: Df = 1.5 m, ф′ = 25°, c′ = 70 kN/m2. Using Eq. (6.28) and FS = 3, determine the net allowable load [see Eq. (6.24)] the foundation could carry.
Figure P6.9
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A column foundation (Figure P4.5) is 3 m x 2 m in plan. Given: Df = 1.5 m, Φ' = 25°, c' = 70 kN/m2. Using Eq. (4.26) and FS = 3, determine the net allowable load [see Eq. (4.22)] the foundation could carry.
An eccentrically loaded continuous foundation is
shown in Figure P6.18. Determine the ultimate
load Qu per unit length that the foundation can
carry. Use the reduction factor method [Eq.
(6.67)].
4 ft
2 ft
Figure P6.18
Qu
2 ft →
-5 ft
Y = 105 lb/ft³
Groundwater table
Ysat 118 lb/ft³
c' = 0
$' = 35°
=
Prob. 3): A square shallow foundation is shown below. If the load eccentricity is 0.3 m,
determine the maximúm allowable load that the foundation can carry. Use Mayerhof's
method, and FS as 4.
(Eccentricity
in one direction
only) e = 0.3 m
Qal
Y = 16.3 kN/m3
c' = 20 kN/m?
p'=28°
1.0 m
1.5 m X 1.5 m
Centerline
Chapter 6 Solutions
Principles of Foundation Engineering (MindTap Course List)
Ch. 6 - For the following cases, determine the allowable...Ch. 6 - A 5.0 ft wide square footing is placed at 3.0 ft...Ch. 6 - Prob. 6.3PCh. 6 - Redo Problem 6.2 using the general bearing...Ch. 6 - The applied load on a shallow square foundation...Ch. 6 - A 2.0 m wide continuous foundation carries a wall...Ch. 6 - Determine the maximum column load that can be...Ch. 6 - A 2.0 m wide strip foundation is placed in sand at...Ch. 6 - A column foundation (Figure P6.9) is 3 m × 2 m in...Ch. 6 - For the design of a shallow foundation, given the...
Ch. 6 - An eccentrically loaded foundation is shown in...Ch. 6 - Prob. 6.12PCh. 6 - For an eccentrically loaded continuous foundation...Ch. 6 - A 2 m 3 m spread footing placed at a depth of 2 m...Ch. 6 - Prob. 6.15PCh. 6 - A tall cylindrical silo carrying flour is to be...Ch. 6 - A 2.0 m 2.0 m square pad footing will be placed...Ch. 6 - An eccentrically loaded continuous foundation is...Ch. 6 - A square foundation is shown in Figure P6.19. Use...Ch. 6 - The shallow foundation shown in Figure 6.25...Ch. 6 - Consider a continuous foundation of width B = 1.4...
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- A column foundation (Figure P3.5) is 3 m x 2 m in plan. Given: D; = 2 m, o' = 25°, c' = 50 kN/m². Using Eq. (3.23) and FS = 4, determine the net allowable load [see Eq. (3.15)] the foundation could carry. Use bearing capac- ity, shape, and depth factors given in Şection 3.6.arrow_forwardA continuous foundation with a width of 1 m is located on a slope made of clay soil. Refer to Figure 5.19 and let Df = 1 m, H = 4 m, b = 2 m, γ = 16.8 kN/m3, c = cu = 68 kN/m2, Φ= 0, and β = 60°.a. Determine the allowable bearing capacity of the foundation. Let FS = 3.b. Plot a graph of the ultimate bearing capacity qu if b is changed from 0 to 6 m.arrow_forwardAn eccentrically loaded foundation is shown in Figure P3.9. Use FS of 4 and determine the maximum allowable load that the foundation can carry. Use Meyerhof's effective area method and the bearing capacity, shape, and depth factors given in Section 3.6.arrow_forward
- A square column foundation has to carry a gross allowable load of 1805 kN (FS = 3). Given: Df = 1.5 m, γ = 15.9 kN/m3 ϕ = 34 and c′ = 0. Use Terzaghi’s equation to determine the size of the foundation (B). The applied load on a shallow square foundation makes an angle of 15° with the vertical. Given: B = 1.83 m, Df = 0.91 m, γ = 18.08 kN/m3 ,ϕ=25° , and c′ = 23.96 kN/m2 . Use FS = 4 and determine the gross allowable (vertical component) load. Use Eq. (16.9).arrow_forward" (a) Qu 1 Qu 3 B (b) M M → X M Qu M (c) Figure 4.24 Analysis of foundation with two-way eccentricity 7 = 17kN/m³ friction angle = : 35⁰° , and cohesion c = 0 Qu (d) The shallow foundation is shown in Figure 4.24 measures 1.5 m X 2.25 m and is subjected to a centric load and a moment. If ев = = 0.12m e₁ eL = 0.36m and the depth of the foundation is 0.8 m, determine the allowable load the foundation can carry. Use a factor of safety of 4. For the soil, we are told that unit weightarrow_forwardA square foundation is 1.5 m x 1.5 m in plan. The soil supporting the foundation has a friction angle = 32 deg. and c = 21 kPa. The unit weight of soil is 17.5 kN/m3. Assume that the depth of foundation Df is 1 meter, Use Nc = 44.14 ; Nq = 28.52 and N? = 26.87. a).Determine the allowable bearing capacity on the foundation with a factor of safety of 3.0 b.)Determine the allowable gross load on the foundation with a factor of safety of 4.0 .arrow_forward
- Q6. A column foundation (Figure below) is 3 m X 2 m in plan. Given: De = 1.5 m, o = 25°, c= 70 kN/m . Terzaghi's equation and assume general shear failure in soil and FS = 3, determine the net alowable koad. y = 17 kN/m 1.5 m 3 m x 2 m Yat = 19.5 kN/m Groundwater levelarrow_forwardA square column foundation has to carry a gross allowable load of 1805 kN ( FS = 3). Given: D f = 1.4 m, γ = 15.4 kN/m 3 , ϕ ′ = 34 ° , and c ′ = 0. Use Terzaghi's equation to determine the size of the foundation ( B ). Assume general shear failure.arrow_forward7.5 A 2.0 m wide square foundation is placed at 0.5 m depth in a saturated clay where c, = 40 kN/m² and y = 19.0 kN/m³. There is a very stiff stratum present at 1.0 m below the foundation. Determine the ultimate bearing capacity using Buisman's (1940) equation.arrow_forward
- Consider a continuous foundation of width B = 1.4 m on a sand deposit with c' = 0, Φ' = 38° and γ = 17.5 kN/m3. The foundation is subjected to an eccentrically inclined load (see Figure 4.31). Given: load eccentricity e = 0.15 m, Df = 1 m, and load inclination β = 18°. Estimate the failure load Qu(ei) per unit length of the foundation a. for a partially compensated type of loading [Eq. (4.85)] b. for a reinforced type of loading [Eq. (4.86)]arrow_forward10. A flexible foundation is subjected to a uniformly distributed load of q-500 kN/m². Table 3 could be useful. Determine the increase in vertical stress, in kPa, Aoz at a depth of z=3m under point F. B 4m 3m 6m E 10m Table 10.3 Variation of I, with m and n m 0.1 0.2 0.3 0.4 0.5 0.6 0.7 0.8 0.9 1.0 0.1 0.0047 0.0092 0.0270 0.0279 0.2 0.0132 0.0092 0.0179 0.0259 0.0132 0.0259 0.0374 0.0222 0.0242 0.0435 0.0474 0.0629 0.0686 0.0258 0.0504 0.0528 0.0547 0.3 0.0731 0.0766 0.0794 0.4 0.1013 0.5 0.0198 0.0387 0.1202 0.6 0.0222 0.0435 0.7 0.0242 0.0474 0.0947 0.1069 0.1168 0.1247 0.1311 0.1361 0.1365 0.1436 0.1491 0.1537 0.1598 0.0168 0.0198 0.0328 0.0387 0.0474 0.0559 0.0168 0.0328 0.0474 0.0602 0.0711 0.0801 0.0873 0.0931 0.0977 0.0559 0.0711 0.0840 0.0947 0.1034 0.1104 0.1158 0.0629 0.0801 0.0686 0.0873 0.1034 0.8 0.0258 0.0504 0.0731 0.0931 0.1104 0.9 0.0270 0.0528 0.0766 0.0977 0.1158 0.0794 0.1013 0.1202 0.0832 0.1263 1.4 0.1300 1.6 0.0306 0.0599 0.0871 0.1114 0.1324 1.8 0.0309 0.0606…arrow_forward1. For the following cases, determine the allowable gross vertical load bearing capacity of the foundation. Use Terzaghi's equation. Part В D; Foundation Type 3 ft 3 ft 28° 400 psf 110 pcf Continuous a b 1.5 m 1.2 m 35° 17.8 kN/m³ Continuous 3 m 30° 30° 16.5 kN/m³ Square 2. A square foundation has to carry gross allowable load of 1805 kN (FS=3). Given: D; = 1.5 m, y=15.9 kN/m³, 0=34°, and c = 0. Use Terzaghi's equation to determine the size of the foundation (B).arrow_forward
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