Concept explainers
Research has shown that people are more likely to show dishonest and self-interested
behaviors in darkness than in a well-lit environment (Zhong, Bohns, & Gino, 2010). In one
experiment, participants were given a set of 20 puzzles and were paid $0.50 for each one
solved in a 5-minute period. However, the participants reported their own performance and
there was no obvious method for checking their honesty. Thus, the task provided a clear
opportunity to cheat and receive undeserved money. One group of participants was testing in a
room with dimmed lighting and a second group was tested in a well-lit room. The reported
number of solved puzzles was recorded for each individual. The following data represent results
similar to those obtained in the study.
Well-Lit Room Dimly-Lit Room
7 9
8 11
10 13
6 10
8 11
5 9
7 15
12 14
5 10
a) Is there a significant difference in reported performance between the two
conditions? Use a two-tailed test with = .01. (If you are unsure how to do this, you
can instead conduct a two-tailed test with = .05.)
b) Compute Cohen’s d to estimate the size of the treatment effect
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- Exercise is known to produce positive psychological effects. Interestingly, not all exercise is equally effective. It turns out that exercising in a natural environment (e.g., jogging in the woods) produces better psychological outcomes than exercising in urban environments or in homes (Mackay & Neill, 2010). Suppose that a sports psychologist is interested in testing whether there is a difference between exercise in nature and exercise in the lab with respect to post-exercise anxiety levels. The researcher recruits n 5 7 participants who exercise in the lab and exercise on a nature trail. The data below represent the anxiety scores that were measured after each exercise session. Treat the data as if the scores are from an independent-measures study using two separate samples, each with n 5 7 participants. Compute the pooled variance, the estimated standard error for the mean difference, and the independent-measures t statistic. Using a 5 .05, is there a significant difference…arrow_forwardMany fundraisers ask for donations using email and text messages. A paper describes an experiment to investigate whether the proportion of people who make a donation when asked for a donation by email is different from the proportion of people who make a donation when asked for a donation in a text message. In this experiment, 1.7% of those who received and opened an email request for a donation and 7.8% of those who received a text message asking for a donation actually made a donation. Assume that the people who received these requests were randomly assigned to one of the two groups (email or text message) and suppose that the given percentages are based on sample sizes of 2,000 (the actual sample sizes in the experiment were much larger). (Let p1 be the proportion who make a donation after receiving an email, and p2 be the proportion who make a donation after receiving a text message.) Find the test statistic and P-value. (Use a table or SALT. Round your test statistic to two…arrow_forwardThe spotlight effect refers to overestimating the extent to which others notice your appearance or behavior, especially when you commit a social faux pas. Effectively, you feel as if you are suddenly standing in a spotlight with everyone looking. In one demonstration of this phenomenon, Gilovich, Medvec, and Savitsky (2000) asked college students to put on a Barry Manilow T-shirt that fellow students had previously judged to be embarrassing. The participants were then led into a room in which other students were already participating in an experiment. After a few minutes, the participant was led back out of the room and was allowed to remove the shirt. Later, each participant was asked to estimate how many people in the room had noticed the shirt. The individuals who were in the room were also asked whether they noticed the shirt. In a similar study with N = 36 participants, the individuals who wore the shirt produced an average estimate of X = 1.8 with SS = 425. (a) Compute a 95%…arrow_forward
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