Repeat Example 7.7 for 3-in schedule 40 pipe with water flowing at 8 ft/s and pressure 30 psig throughout.

Introduction to Chemical Engineering Thermodynamics
8th Edition
ISBN:9781259696527
Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Publisher:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Chapter1: Introduction
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Answer 7.13 please!

7.7.
In Examples 7.3 and 7.4 the analysis was simple because
the jet was at right angles to the solid surface. You can
observe with a garden hose that such jets, perpendicular
to walls or sidewalks, go off radially in all directions,
with more or less circular symmetry. You will also
observe that there is a region near the jet that is much
shallower than the rest, as shown in Fig. 7.23 and
described in Sec. 7.5.3. A more interesting and complex
problem is the flow of a jet against a flat surface that is
not perpendicular to you can also observe this flow
with a garden hose. The flow is more or less circularly
symmetrical, but much more goes away in the direction
away from the hose than in the direction toward the hose.
But why does any of it flow back in the direction toward
the hose?
We can understand this if we replace the three-dimensional
problem (circular jet, moving in x, y, and z) directions with a
two-dimensional jet (as might issue from a rectangular slot) that
is constrained to move only in the x and y directions (by
directing it into an open rectangular channel, which prevents
flow in the z direction). This flow is sketched in Fig. 7.27.
Friction is assumed to be negligible, so from B.E. (ignoring
gravity) we see that both streams flowing along the wall must
have the same velocity as that in the jet, V₁. In the figure the
stream going off to the upper right, (2), is larger than that going
to the lower left, (3), in accord with the observation described
above. If the flow is frictionless, then there can be no shear stress
on the wall, so the resisting force must act normal to the surface
as shown. We could attempt to solve for these flows by writing
the x and y components of the steady flow momentum balance,
but that adds more terms and only makes the analysis harder (try
it!).
Instead, we choose a new set of axes for our momentum
balance, with one axis, the s direction, parallel to the plate and
the other, the r direction, perpendicular to the plate, as sketched
on Fig. 7.27. We now apply Eq. 7.17 in the s direction, finding
Transcribed Image Text:7.7. In Examples 7.3 and 7.4 the analysis was simple because the jet was at right angles to the solid surface. You can observe with a garden hose that such jets, perpendicular to walls or sidewalks, go off radially in all directions, with more or less circular symmetry. You will also observe that there is a region near the jet that is much shallower than the rest, as shown in Fig. 7.23 and described in Sec. 7.5.3. A more interesting and complex problem is the flow of a jet against a flat surface that is not perpendicular to you can also observe this flow with a garden hose. The flow is more or less circularly symmetrical, but much more goes away in the direction away from the hose than in the direction toward the hose. But why does any of it flow back in the direction toward the hose? We can understand this if we replace the three-dimensional problem (circular jet, moving in x, y, and z) directions with a two-dimensional jet (as might issue from a rectangular slot) that is constrained to move only in the x and y directions (by directing it into an open rectangular channel, which prevents flow in the z direction). This flow is sketched in Fig. 7.27. Friction is assumed to be negligible, so from B.E. (ignoring gravity) we see that both streams flowing along the wall must have the same velocity as that in the jet, V₁. In the figure the stream going off to the upper right, (2), is larger than that going to the lower left, (3), in accord with the observation described above. If the flow is frictionless, then there can be no shear stress on the wall, so the resisting force must act normal to the surface as shown. We could attempt to solve for these flows by writing the x and y components of the steady flow momentum balance, but that adds more terms and only makes the analysis harder (try it!). Instead, we choose a new set of axes for our momentum balance, with one axis, the s direction, parallel to the plate and the other, the r direction, perpendicular to the plate, as sketched on Fig. 7.27. We now apply Eq. 7.17 in the s direction, finding
7.13. Repeat Example 7.7 for 3-in schedule 40 pipe with water
flowing at 8 ft/s and pressure 30 psig throughout.
Transcribed Image Text:7.13. Repeat Example 7.7 for 3-in schedule 40 pipe with water flowing at 8 ft/s and pressure 30 psig throughout.
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