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-TA XA 0.0 mol m³.sec (m³-sec) -TA FAO (m³-sec -TA mol 0.49 0.1 (A) Calculate values of 0.41 0.2 0.34 0.4 0.199 Reaction AB 0.6 0.117 FAO -and-TA to fill in the empty rows in the table above. mol sec PureA T = 500K & P = 830 kPa (8.2 atm) Feed Flow Rate = 0.8 0.7 0.083 0.8 0.054

-TA XA 0.0 mol m³.sec (m³-sec) -TA FAO (m³-sec -TA mol 0.49 0.1 (A) Calculate values of 0.41 0.2 0.34 0.4 0.199 Reaction AB 0.6 0.117 FAO -and-TA to fill in the empty rows in the table above. mol sec PureA T = 500K & P = 830 kPa (8.2 atm) Feed Flow Rate = 0.8 0.7 0.083 0.8 0.054

Introduction to Chemical Engineering Thermodynamics
Introduction to Chemical Engineering Thermodynamics
8th Edition
ISBN:9781259696527
Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Publisher:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Chapter1: Introduction
Section: Chapter Questions
Problem 1.1P
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XA 0.0 mol m³.sec. -(m³.sec) mol -TA -TA FAO (m³-sec -TA mol 0.49 0.1 0.41 (A) Calculate values of an and 0.2 0.34 0.4 0.199 Reaction A → B 0.6 0.117 Feed Flow Rate = 0.8- FAO to fill in the empty rows in the table above. -TA mol sec PureA T = 500K & P = 830 kPa (8.2 atm) 0.7 0.083 0.8 0.054
Transcribed Image Text:XA 0.0 mol m³.sec. -(m³.sec) mol -TA -TA FAO (m³-sec -TA mol 0.49 0.1 0.41 (A) Calculate values of an and 0.2 0.34 0.4 0.199 Reaction A → B 0.6 0.117 Feed Flow Rate = 0.8- FAO to fill in the empty rows in the table above. -TA mol sec PureA T = 500K & P = 830 kPa (8.2 atm) 0.7 0.083 0.8 0.054
Expert Solution
Step 1: Introduction to the question:

A reaction, Arightwards arrowB is given with following information,

Feed flow rate, FA0 = 0.8 mol over sec

Pure reactant A is present.

Temperature, T = 500 K and Pressure, P = 830 kPa

Conversion (XA) and rate equation values are given in the table.

The empty columns of table is to be filled.

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