In the circuit of the figure below, the switch S has been open for a long time. It is then suddenly closed. Take = 10.0 V, R1 = 43.0 kΩ, R2 = 180 kΩ, and C = 14.0 µF.(a) Determine the time constant before the switch is closed.(b) Determine the time constant after the switch is closed.(c) Let the switch be closed at t = 0. Determine the current in the switch as a function of time. (Assume I is in A and t is in s. Do not enter units in your expression. Use the following as necessary: t.)I keep messing up part C. any help you can give and explain would be appreciated. R₁SR₂с In the circuit of the figure below, the switch S has been open for a long time. It is then suddenly closed. Take & = 10.0 V, R₁ = 43.0 kN, R₂ = 180 kſ, and C = 14.0 μF.R₁WESI =(a) Determine the time constant before the switch is closed.3.122SR₂(b) Determine the time constant after the switch is closed.2.52SC(c) Let the switch be closed at t = 0. Determine the current in the switch as a function of time. (Assume I is in A and t is in s. Do not enter units in your expression. Use thefollowing as necessary: t.)2.52252 + 55.5eμAX

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R₁ www S R₂ C

Delmar's Standard Textbook Of Electricity

7th Edition

ISBN:9781337900348

Author:Stephen L. Herman

Publisher:Stephen L. Herman

Chapter18: Resistive-inductive Parallel Circuits

Section: Chapter Questions

Problem 1PA: Incandescent lighting of 500 W is connected in parallel with an inductive load. A clamp-on ammeter...

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Concept explainers

HVDC

HVDC stands for high voltage direct current in the electric power transmission system. The high voltage direct current system uses direct current (DC) for the transmission of electrical power through transmission lines in contrast with the alternating current that is the AC system. The HVDC is used to transmit bulk power point-to-point through long distances transmission lines. Power is rapidly transferred because the efficiency of transmission lines is greatly increased over long distances due to HVDC lines.

Question

In the circuit of the figure below, the switch S has been open for a long time. It is then suddenly closed. Take = 10.0 V, R₁ = 43.0 kΩ, R₂ = 180 kΩ, and C = 14.0 µF.

(a) Determine the time constant before the switch is closed.

(b) Determine the time constant after the switch is closed.

(c) Let the switch be closed at t = 0. Determine the current in the switch as a function of time. (Assume I is in A and t is in s. Do not enter units in your expression. Use the following as necessary: t.)

I keep messing up part C. any help you can give and explain would be appreciated.

In the circuit of the figure below, the switch S has been open for a long time. It is then suddenly closed. Take & = 10.0 V, R₁ = 43.0 kN, R₂ = 180 kſ, and C = 14.0 μF.
R₁
W
E
S
I =
(a) Determine the time constant before the switch is closed.
3.122
S
R₂
(b) Determine the time constant after the switch is closed.
2.52
S
C
(c) Let the switch be closed at t = 0. Determine the current in the switch as a function of time. (Assume I is in A and t is in s. Do not enter units in your expression. Use the
following as necessary: t.)
2.52
252 + 55.5e
μA
X

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