Human Anatomy & Physiology (11th Edition)
11th Edition
ISBN: 9780134580999
Author: Elaine N. Marieb, Katja N. Hoehn
Publisher: PEARSON
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- Which fractions measured from your gel filtration experiment had the most and least amount of protein detected? Which fraction likely contained the most myoglobin based off molecular weight and protein presence? Which fraction likely contained the most egg albumin based off molecular weight and protein presence? Which samples measured from your ion exchange experiment had the most protein detected? Calculate the approximate pI of your proteins using the ion exchange Table 2. Ion Exchange Samples Tested by Bradford Assay Concentration BSA (μg/mL) Concentration BSA (mg/mL) Volume of Sample added to Bradford Reagent (μL) Absorbance at 595 nm Standard 1 250 0.25 50 0.32 Standard 2 125 0.125 50 0.16 Standard 3 62.5 0.0625 50 0.08 Standard 4 31.25 0.03125 50 0.04 Standard 5 15.625 0.015625 50 0.02 Blank 0.00 0.00 0.00 Table 3. Gel Filtration Fractions Tested by Bradford Assay Fraction #:…arrow_forwardQuestion 4 Which of the following would typically be the initial indicator of bacteria growing within a blood culture tube? O An automated incubator will detect fluorescence. O Bacterial colonies will appear on MacConkey agar. Bacterial colonies will appear on blood agar. Centrifugation will cause sediment to appear at the end of the tube.arrow_forwardAarrow_forward
- Activity 13 Urine Culture Inoculating Urine with a calibrated loop The number of microorganisms per milliliter recovered on urine culture can aid in the differential diagnosis of urinary tract infection (UTI). Plastic or wire inoculating loop available commercially, have been calibrated to deliver a known volume of liquid when handled correctly, thus enabling the microbiologist to estimate numbers of organism in the original specimen based on colony forming unit (CFU) of growth on cultures. PROCEDURE: 1st day 1. Gently swirl the specimen bottle to mix the urine specimen. 2. Label all plated media with name of patients, clinical specimen used and date. Label at the bottom of plates and not on the cover. 3. Obtain a disposable calibrated loop. 4. Dip the loop straight into the urine specimen so that the loop part is completely covered. Withdraw straight out. See fig. 16-18 5. Inoculate blood agar plate (BAP) as shown in fig.16-19 6. Incubate at 35 – 37˚C for 18 – 24 hours. 7. Dispose…arrow_forwardDevelop a spreadsheet to predict as functions of time with concentration, volimme and permeate flows for a batch ultrafiltration. Assume that the flux depends on concentration as follows: J(L/M²/H) = A*EXP(-bC) where C is the retentate concentration in g/l. Assume that the recirculation rate is kept high enough that shear rate dependence is eliminated. Do a sample run with C.= 0.5 g/l, Cfinal = 50 g/l, A = 50, and b = 0.02. Assume a filtration area of 19.4M² and an initial volume of 3255 L. Assume σ (protein) = 1.0 or σ (protein) = 0.95 or σ (protein) = 0.90.arrow_forwardTube # 2c Table 3-Determination of the optimum temperature of catechol oxidase enzyme. 1st Absorbance 0 min. at Expt. Temp. 3c 4c Q12) After 10 min at experimental temperature was enzyme activity high or low at 75°C and 100°C? Support your answer by looking at the difference between 2nd and 1st absorbances. ( 5c Q13) Was the enzyme denatured at 75°C and/or 100°C% Support your answer by looking at what happens after returning enzyme to room temperature AFTER enzyme was subjected to experimental temperatures of 20 °C,40 °C,60 °C,80 °C and 100°C. "¹ /1 Q14) What happens to the enzyme structure and function when it becomes denatured? ( Potato Expt. extract Temp. (mL) 2 2 2 2 room temp 20 °C 40 °C 75 °C Boiling 100 °C dH₂O Catechol (mL) (mL) 0 0 0 0 13 || 13 13 13 Start Time: 4:20 Absorbance: 0.072 Start Time: 4:25 Absorbance: 0.114 Start Time: 4:25 Absorbance: 0.132 Start Time: 4:27 Absorbance: 0.097 2nd Absorbance after 10 min. in Expt Temp. Time for reading: 4:30 Absorbance: 0.128 Time…arrow_forward
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