Question 2) A full-wave rectifier with ohmic load given in the figure below feeds a 75 Q load and the effective (rms) value of the source voltage is 220V, its frequency is 50 Hz. Accordingly, find the following desired circuit parameters: a) the peak voltage of the source, b) the peak current of the load, c) Average stress of the load,
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- How is a solid-state diode tested? Explain.A half-wave rectifier with ohmic load given in the figure below feeds a 50 Q load and the peak value of the source voltage is 311V and the frequency is 50 Hz. Accordingly, find the following desired circuit parameters: a) Effective (rms) voltage of the source, b) the peak current of the load, c) Average stress of the load, d) Average current of the load, e) The effective (rms) voltage of the load, f) Effective (rms) current of the load, g) Power of the load + vD RDesign a single-phase full wave bridge rectifier with input voltage of 100v and inductive load of 10ohm and 40mH a. Show the waveform relation between the I/P and O/P b. Calculate the average O/P voltage c. Calculate the rms current
- A single phase – half wave controlled rectifier with freewheeling diode is supplying a load consistingseries connected a resistor and an inductance from a 70.7V (RMS), 50Hz sinusoidal AC source.The firing delay of the thyristor is 90° and the load values are R=10Ω, L=0.1 H. Define the loadcurrent expression and draw the load current by calculating for first two periods. And calculate theaverage values of the load voltage and current.Power supply circuit is delivering 0.5 A and an average voltage 20 V to the load as shown in the circuit below. The ripple voltage of the half wave rectifier is 0.5 V and the diode is represented using constant voltage model. The smoothing capacitor value is equal to 220V rmsh soHz} VL-DC =20V 0.01 F 0.02 F 0.0167 F None of the aboveQuestion 3) An ohmic loaded half-wave controlled rectifier given in the figure below feeds a 25 Q load and the peak value of the source voltage is 350V and its frequency is 50 Hz. Accordingly, find the following desired circuit parameters: a) Effective (rms) voltage of the source, b) the peak current of the load, c) Average stress of the load, d) Average current of the load, e) The effective (rms) voltage of the load, f) Effective (rms) current of the load, g) Power of the load K R
- Note: Answer All question 1: A) For a single-phase half-wave uncontrolled rectifier with (RL) load, find the rms value of the output voltage (V) and form factor (FF%) with supply voltage: v,(t) = 10 sin(wt). Draw the circuit diagram and sketch the voltages and current waveforms. The conduction angle B = 220°. %3DThe Figure 2 shows an electronic circuit designed for supplying power to a load (R1). The supply voltage 235V (RMS, AC) at frequency of 50HZ. The required DC voltage and power for the load are 24V and 3.6 W respectively. The Electrical Components of this AC to DC converter are: A full-wave rectifier to convert AC voltage to DC voltage. A regulator with transistor and Zener diode to ensure a constant voltage and power for the load. D1 Iide 91 Vaut VLoad D2 D3 Vde VI sine R1 RL Regulate Reetifier Figure 2. Complete Circuit Assume that the diodes are real diodes (NOT ideal diodes). The following information is available: The collector to base resistor of the regulator R1 = 5.0 k The transistor Q1 with B value of 24 is used for the regulator circuit. Determine the following quantities for this electronic device and fill the table below: Question Answer The voltage of Zener Diode (Vz) The current in R1 The DC current into the regulator | (Idc) Base current of transistor (IB) Collector…Three-phase half wave rectifier supply resistive load with DC power of 4 kW; the ammeter connected with D1 indicates 8 A r.m.s current, and the source frequency is 50 Hz Due to system inductance the average voltage drops to 96.2% of idealized value ( when the inductance is neglected). How much will the average and r.m.s voltage s be? The r.m.s phase current and average load current Is=? & Idc=? The secondary r.m.s voltage and transformer capacity Vs & KVA? The inductances causes the voltage drop Lc=? The diode forward current and maximum inverse voltage? Now, if the phase B is failed ( disconnected), how much with new dc voltage be in %..Vdc=….% ??
- Question 4) A full wave controlled rectifier with ohmic load given in the figure below feeds a 10 Q load and the effective (rms) value of the source voltage is 110V and its frequency is 60 Hz. Accordingly requested below Find the circuit parameters: a) the peak voltage of the source, b) the peak current of the load, c) Average stress of the load, d) Average current of the load, e) The effective (rms) voltage of the load, f) Effective (rms) current of the load, SCR 1 SCR 2 is R g) Power of the load SCR 3 t* SCR 4A R-load half-wave rectifier used sinusoidal voltage source with a peak value (35.353kV). The firing angle is (30). The total resistance is 50k2 and frequency is 50HZ. Calculate (in details): load direct voltage, maximum direct voltage, normalized voltage and effective voltage, power delivered to the load, power factor, form factor, ripple factor?3 Given the bridge-type full-wave rectifier circuit shown 220V 60Hz 220V:Es Es D1 D2 D3 D4 The load resistor is 220 and the transformer average current is 300mA. Determine: (a) Average value, RMS value, and frequency of load voltage VRL. (b) Average current and PIV of each diode. RL