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Q1: Consider a machine with a byte addressable main memory of bytes and block size of 8 bytes. Assume that a direct mapped cache consisting of 32 lines is used with this machine. How is a 12-bit memory address divided into tag, line number, and byte number? Block size =8byte (2³), so 3bits. Cache of 32 lines (25), so 5bits. TAG LINES WORD 4 5 3 Into what line would bytes with each of the following addresses be stored? 0001 0001 0001 TAG LINES WORD 0001 00010 001 Line: 1 0011 0011 0100 TAG LINES WORD 0011 00110 100

Q1: Consider a machine with a byte addressable main memory of bytes and block size of 8 bytes. Assume that a direct mapped cache consisting of 32 lines is used with this machine. How is a 12-bit memory address divided into tag, line number, and byte number? Block size =8byte (2³), so 3bits. Cache of 32 lines (25), so 5bits. TAG LINES WORD 4 5 3 Into what line would bytes with each of the following addresses be stored? 0001 0001 0001 TAG LINES WORD 0001 00010 001 Line: 1 0011 0011 0100 TAG LINES WORD 0011 00110 100

Computer Networking: A Top-Down Approach (7th Edition)
Computer Networking: A Top-Down Approach (7th Edition)
7th Edition
ISBN:9780133594140
Author:James Kurose, Keith Ross
Publisher:James Kurose, Keith Ross
Chapter1: Computer Networks And The Internet
Section: Chapter Questions
Problem R1RQ: What is the difference between a host and an end system? List several different types of end...
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Q1: Consider a machine with a byte addressable main memory of bytes and block size of 8 bytes. Assume that a direct mapped cache consisting of 32 lines is used with this machine. How is a 12-bit memory address divided into tag, line number, and byte number? Block size =8byte (2³), so 3bits. Cache of 32 lines (2), so 5bits. TAG LINES WORD 4 5 3 Into what line would bytes with each of the following addresses stored? 0001 0001 0001 TAG LINES WORD 0001 00010 001 Line: 1 0011 0011 0100 TAG LINES WORD 0011 00110 100 Line: 4
Transcribed Image Text:Q1: Consider a machine with a byte addressable main memory of bytes and block size of 8 bytes. Assume that a direct mapped cache consisting of 32 lines is used with this machine. How is a 12-bit memory address divided into tag, line number, and byte number? Block size =8byte (2³), so 3bits. Cache of 32 lines (2), so 5bits. TAG LINES WORD 4 5 3 Into what line would bytes with each of the following addresses stored? 0001 0001 0001 TAG LINES WORD 0001 00010 001 Line: 1 0011 0011 0100 TAG LINES WORD 0011 00110 100 Line: 4
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