Problem. Determine KM and V,for an enzyme from the following data :maxS (mM) vo (µM.s*)1/S (mM) 1/v.(µM .s*)2.51.000.40240.500.2556.30.200.16107.60.100.13200.050.11↑

Enzymes are protein molecules that increase the rate of reaction by decreasing the activation…

Answered: Problem. Determine KM and Vmax for an…

Biochemistry

9th Edition

ISBN:9781319114671

Author:Lubert Stryer, Jeremy M. Berg, John L. Tymoczko, Gregory J. Gatto Jr.

Publisher:Lubert Stryer, Jeremy M. Berg, John L. Tymoczko, Gregory J. Gatto Jr.

Chapter1: Biochemistry: An Evolving Science

Section: Chapter Questions

Problem 1P

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2. Enzyme-catalyzed reactions. Answer the following with true or false. If false, explain why. (a) The initial rate of an enzyme-catalyzed reaction is independent of substrate concentration. (b) At saturating levels of substrate, the rate of an enzyme-catalyzed reaction is proportional to the enzyme concentration. (c) The Michaelis constant Km equals the substrate concentration at which velocity (v) = Vmax/2. (d) The Km for a regulatory enzyme varies with enzyme concentration. (e) If enough substrate is added, the normal Vmax of an enzyme-catalyzed reaction can be attained even in the presence of a noncompetitive inhibitor. (f) The Km of some enzymes may be altered by the presence of metabolites structurally unrelated to the substrate. (g) The rate of an enzyme-catalyzed reaction in the presence of a rate-limiting concentration of substrate decreases with time. (h) The sigmoidal shape of the v versus [S] curve for some regulatory enzymes indicates that affinity of the enzyme for the…
Dropdown Choices 1. a) 20 b)10 c)30 2. a) 10 b) 5 c) 20 d) 2
V 23. The graph below is a graph of Vmax (a) Label the graph clearly with both the Vmax and the Km. Estimate the Km from this graph giving the correct units. v/Vmax 1.0 0.5 0.0 0.0 vs [S] for an enzyme. Enzyme Activity vs [Substrate] :0.2 0.4 Substrate (HM): 0.6 (b) If the Vmax = 25 mmoles per minute per µmole of enzyme calculate the Keat and the specificity constant."
Please explain your reasoning for every answer
In Lineweaver Burk plot: O a. The slope of the plot is the Vmax/Km O b. The intercept on X-axis is 1/Km. O c. The intercept on y-axis is 1/Vmax O d. double-reciprocal plot of enzyme kinetics is generated, where 1/VO is plotted as a function [S]. O e. All answers are correct
The effect of an inhibitor I on the rate of a single-substrate, enzyme-catalyzed reaction was investigated and gave the following results (See table below). a. What is the mode of action (pure competitive, mixed competitive, uncompetitive or noncompetitive) of the inhibitor? Briefly explain your answer. b. Estimate the value of Km and Vmax for uninhibited reaction.
a. What is the Vmax of this enzyme WITHOUT inhibitor? Please show your work. b. What is the Km of this enzyme WITHOUT inhibitor? Please show your work. c. The specificity constant of enzyme X is 8 x 10^7 /(M * seconds) What is the kcat of enzyme X WITHOUT inhibitor? Please show your work d. What was the concentration of enzyme used for measuring the kinetics of enzyme X WITHOUT inhibitor? Please show your work
2.3
Deepika_Biology From a kinetics experiment, Kcat was determined to be 55sec^-1. For the kinetic assay, 0.05mL of a 0.05mg/mL solution of the enzyme was used, and the enzyme has a molecular weight of 30,000g/mole. Assume a reaction volume of 3mL. Calculate Vmax (um*min^-1) for the enzyme and catalytic efficiency (in M^-1sec^-1) for the enzyme. The Km for the enzyme was determined to be 8.3*10^-2M.
Please answer asap and in short
Answer #2
Part 1: Assess the following partial results section below by editing it for brevity by omitting any unnecessary parts (1 point), explain why you decided to remove certain sections (1 point): To evaluate inhibitory effects of the selected molecules, 10mM stock solutions of each molecule were prepared in DMSO. A reaction mixture (200μl) was prepared with the same formula optimized for the enzyme activity assay (0.1 M Tris-HCl ph 8, 0.1 M KCI, 25 mM NaCl, 0.25 mM ATP, and two units of inorganic yeast pyrophosphatase) with 10 µM of the sample molecule. The reaction mixture was incubated for 20 minutes at ambient temperature. Enzymatic reaction was triggered by addition of the substrate B (0.2 mM) and the absorbance of the product was monitored at 290 nm for 10 minutes. Six out of 15 sample molecules showed appreciable inhibition at 10 μM (Figure 5). Three of the molecules, A3, A6, and A7 exhibited more than 50% inhibition of the enzyme activity and were further diluted to find the minimal…

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Problem. Determine KM and Vmax for an enzyme from the following data : S(mM) vo(HM.s²) 1/S (mM) 1/v.(µM.s*) 1 2.5 1.00 0.40 2 4 0.50 0.25 5 6.3 0.20 0.16 10 7.6 0.10 0.13 20 9 0.05 0.11