Problem 2A sector of a steel plate with endurance limit Se = 400 MPa, and ultimate strength Sut = 1000 MPa,has a stress state defining with the following cycle parameters calculated with von Mises criterion:= 130 MPaσησαmax-Misesmax-Mises= = 400 MPa.Calculate the useful life in cycles according to Goodman criterion considering an equivalent cycle ofcompletely inverted stress. Take n = 1 and work it in in sector of high cycle and finite life.

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Answered: Problem 2 A sector of a steel plate…

Mechanics of Materials (MindTap Course List)

9th Edition

ISBN:9781337093347

Author:Barry J. Goodno, James M. Gere

Publisher:Barry J. Goodno, James M. Gere

Chapter3: Torsion

Section: Chapter Questions

Problem 3.7.8P: A tubular shaft being designed for use on a construction site must transmit 120 kW at 1,75 Hz, The...

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Two sections of steel drill pipe, joined by bolted flange plates at Ä are being tested to assess the adequacy of both the pipes. In the test, the pipe structure is fixed at A, a concentrated torque of 500 kN - m is applied at x = 0.5 m, and uniformly distributed torque intensity t1= 250 kN m/m is applied on pipe BC. Both pipes have the same inner diameter = 200 mm. Pipe AB has thickness tAB=15 mm, while pipe BC has thickness TBC= 12 mm. Find the maximum shear stress and maximum twist of the pipe and their locations along the pipe. Assume G = 75 GPa.
A 2-in-diameter C1118, as rolled steel shaft rotates at 240 rpm. Assuming a repeated, reversed and gradual loading is applied, determine the maximum horsepower that can be transmitted (hp). Since torsional stress is considered a shearing stress, use the equation Ssy = 0.75 Sy for the design. find, Horsepower, hp
A shaft is loaded in bending and torsion such that Ma = 69 N · m, Ta = 42 N · m, Mm = 52 N · m, and Tm = 31 N · m. For the shaft, Su = 700 MPa and Sy = 560 MPa, and a fully corrected endurance limit of Se = 210 MPa is assumed. Let Kf = 2.2 and Kfs = 1.8. With a diameter of 28 mm, determine the yielding factor of safety using von Mises stress to consider the possibility of static failure in the first load cycle.
Problem 2. A 300-mm diameter solid disk is to be used as a flywheel in a machine to reduce speed fluctuations. If the disk material has yield strength S Y =720 MPa, density p=7000 kg/m^ 3 . and Poisson's ratio J = 0.2 ^ c , find the maximum allowable rotational speed (in rpm) for a safety factor of 1. a) Solve using the MSST. b) Solve assuming that the disk is mad of cast iron having Sut = 207MPa , Fuc = 780MPa, p = 7000 kg/m³, and Poisson's ratio v r = 0.26 , Use Coulomb-Mohr theory.
Find factor of safety if the Ultimate Stress of a ductile material is 250.94 MPa. If the material is subjected to a loading condition that generates the working stress of 151.27 MPa
A 2Hp motor rotates at 1500 rpm. If the allowable torsional stress is not to exceed 40 MPa, what is the minimum diameter of shaft?
A solid cylindrical shaft made of AISI 1020 steel(quenched and tempered at 870oC) rotates at a speedthat produces a safety factor of 2.5 against the stresscausing yielding. To instrument the shaft, a small hole isdrilled in its center for electric wires. At the same timethe material is changed to AISI 1080 steel that has beenquenched and tempered at 800oC. Find the safety factoragainst yielding of the new shaft.
A Steel shaft is subjected to an end thrust producing a stress of 90 MPa and the minimum shearing stress on the surface arising from torsion is 60 MPa .The yield point stress of the material in simple tension was found to be 300 MPa. calculate the factor of safety of the shaft according to the following theory 1)maximum shear stress theory
Solid Mechanics A steel shaft in the form of a solid body circular rod or a circular tube can be manufactured. Torsion of spindle of 1200 N.m it is required to carry the moment. Anti-slip protection for shaft material stress 40 MPa, the largest permitted unit torsion angle in the bar 0.750 / m and the shear modulus of the steel is G = 78 GPa. a) Find the required diameter d0 for a solid circular shaft. b) Required for a ring-section shaft whose thickness is one tenth of the outer diameter Find the outer diameter d2. c) Diameter ratios (d2 / d0 for ring and solid section shafts. Find the weight ratios with the ratio).
The figure shows a section of a shaft made of annealed steel with yield strength of 600 MPa and ultimate tensile strength of 700 MPa. Diameters of the shaft are D=30 mm and d=20 mm. Fillet radius of the shoulder section is 2.5 mm. The shaft is rotating and subjected to steady bending moment of M=51 Nm, steady torsion of T=58 Nm and steady axial load of F=14 kN. The operating temperature of the shaft is 20 ᵒC and reliability is 99%. The shaft has ground surface.Calculate the mean component of the shear stress (in MPa)
The figure shows a section of a shaft made of annealed steel with yield strength of 600 MPa and ultimate tensile strength of 700 MPa. Diameters of the shaft are D=30 mm and d=20 mm. Fillet radius of the shoulder section is 2.5 mm. The shaft is rotating and subjected to steady bending moment of M=51 Nm, steady torsion of T=58 Nm and steady axial load of F=14 kN. The operating temperature of the shaft is 20 ᵒC and reliability is 99%. The shaft has ground surface. Calculate the alternating component of the normal stress (in MPa). (If there is no alternating component of the normal stress, enter "0" in the answer box)
Using the maximum-shear-stress (MSS) theory determine the factor of safety for a bar of AISI 1020 cold-drawn steel, see Table A-20) with the follwoing stresses: σx = 199 MPa, σy = 76 MPa

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