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Prob 10. using a pointer: int32_t x_cmp_y_load (int32_t x, int32_t y, int16_t *ptra, int32_t *ptrB) { if (x > y) { return (int32_t)*(++ptrA) = 2; } else { 1. Given the following C function for returning a 16-bit or 32-bit value return (ptrB++) / 2; x_cmp_y_load_s PROC CMP B.. cmp_else Rewrite the above C function in assembly with the following start code: ro, ri cmp_then

Prob 10. using a pointer: int32_t x_cmp_y_load (int32_t x, int32_t y, int16_t *ptra, int32_t *ptrB) { if (x > y) { return (int32_t)*(++ptrA) = 2; } else { 1. Given the following C function for returning a 16-bit or 32-bit value return (ptrB++) / 2; x_cmp_y_load_s PROC CMP B.. cmp_else Rewrite the above C function in assembly with the following start code: ro, ri cmp_then

Computer Networking: A Top-Down Approach (7th Edition)
Computer Networking: A Top-Down Approach (7th Edition)
7th Edition
ISBN:9780133594140
Author:James Kurose, Keith Ross
Publisher:James Kurose, Keith Ross
Chapter1: Computer Networks And The Internet
Section: Chapter Questions
Problem R1RQ: What is the difference between a host and an end system? List several different types of end...
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Prob 10. using a pointer: Given the following C function for returning a 16-bit or 32-bit value int32_t x_cmp_y_load (int32_t x, int32_t y, int16_t *ptrA, int32_t *ptrB) { if (x > y) { return (int32_t)*(++ptrA) * 2; } } else { } 1. return *(ptrB++) / 2; x_cmp_y_load_s PROC CMP B.. cmp_else cmp_then cmp_end Rewrite the above C function in assembly with the following start code: cmp_then cmp_else BX ENDP where B.. should be replaced by the appropriate instruction and should be followed by an assembly instruction. Note that we use the positive logic (the same logic as the C if test) to have the else code block before the then code block. Write your code in the space provided in the code. 2. x_cmp_y_load_s PROC CMP B.. cmp_end ro, ri cmp_then 1r Rewrite the above C function in assembly with the following start code: BX ENDP ro, ri cmp_else lr Note that we use the negative logic (the opposite logic of the Cif test) to have the else code block following the then code block. Write your code in the space provided in the code.
Transcribed Image Text:Prob 10. using a pointer: Given the following C function for returning a 16-bit or 32-bit value int32_t x_cmp_y_load (int32_t x, int32_t y, int16_t *ptrA, int32_t *ptrB) { if (x > y) { return (int32_t)*(++ptrA) * 2; } } else { } 1. return *(ptrB++) / 2; x_cmp_y_load_s PROC CMP B.. cmp_else cmp_then cmp_end Rewrite the above C function in assembly with the following start code: cmp_then cmp_else BX ENDP where B.. should be replaced by the appropriate instruction and should be followed by an assembly instruction. Note that we use the positive logic (the same logic as the C if test) to have the else code block before the then code block. Write your code in the space provided in the code. 2. x_cmp_y_load_s PROC CMP B.. cmp_end ro, ri cmp_then 1r Rewrite the above C function in assembly with the following start code: BX ENDP ro, ri cmp_else lr Note that we use the negative logic (the opposite logic of the Cif test) to have the else code block following the then code block. Write your code in the space provided in the code.
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