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Hello. Please answer the attached Computer Organization/Design question correctly & completely. Please show all of your work.
*If you answer the question correctly, I will give you a thumbs up. Thank you.
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- For a direct-mapped cache with 64KİB data, 8-word blocks, and 32-bit addresses, answer the following questions: a) What is the number of blocks/lines in the cache? b) Identify the bits in the 32-bit address that are used as index bits? c) Identify the bits in the 32-bit address that are used as tag bits? d) What is the total number of bits in this cache (including tag field and valid field)? e) Identify the block number in the cache to which the following 32-bit memory address maps: Ox00003Z00 (Hexadecimal notation) where Z is the least significant digit in your student ID (written as a decimal number)For a direct-mapped cache design with 64-bit addresses, the following bits of the address are used to access the cache: Tag Index Offset 63-13 12-4 3-0 a. What is the cache block size (in bytes)?b. What is the cache size (in bytes)?c. What is the total number of bits (including valid bit, tag bits and data array bits) to implement this cache?d. For the same block and cache sizes, you want to implement a 4-way set-associative cache, what is the number of index bit and the number of tag bits?1. For a direct-mapped cache design with a 32-bit address, the following bits of address are used to access the cache. Tag Index Offset 31-14 13-7 6-0 a. What is the cache block size (in words)? b. How many entries does this cache have? c. What is the ratio between total bits required for such a cache implementation over the data storage bits?
- For a direct-mapped cache design with a 32-bit address, the following bitsof the address are used to access the cache. Use the table below. a. What is the cache block size (in words)?b. How many entries does the cache have?c. What is the ration between total bits required for such a cache implementation overthe data storage bit?For a direct-mapped cache design with a 32-bit address, the following bits of the address are used to access the cache. Tag 31-10 Index 9-5 a. What is the cache block size (in words)? b. How many entries does the cache have? Offset 4-0 c. What is the ratio between total bits required for such a cache implementation over the data storage bits?a direct-mapped cache with 128 blocks. The block size is 32 bytes.Find the number of tag bits, index bits, and offset bits in a 32-bit address. Find the number of bits required to store all the valid and tag bits in the cache. Given the following sequence of address references in decimal: 20000, 20004, 20008, 20016, 24108, 24112, 24116, 24120. Starting with an empty cache, show the index (line) and tag for each address and indicate whether a hit or a miss.
- For a direct-mapped cache design with a 32-bit address, the following bits of the address are used to access the cache. We assume that each word has 4 bytes. How many entries does the cache have? Tag Index Offset Block offset | Byte offset 31–12 11-6 5-2 1-0Assume that you have a direct-mapped cache with 16 indices and each block can contain 32 words. Assuming that each bytes address is 32 bits long (and a word is 32 bits), answer the following questions: a). How many bits in each address are used for its tag? bits b). Compute the total number of bits required to implement this cache, including valid bits, tag bits and bits used for data. bitsQ1. For a direct-mapped cache design with a 32-bit address, the following bits of the address are used to access the cache. Tag 31-10 Index 9-5 a) How many words of data in each cache line? b) How many lines does the cache have? c) d) Offset 4-0 What is the cache data size (in bits)? What is the ratio between total bits required for such a cache implementation over the data storage bits?
- Consider a 32-bit physical memory space and a 32 KiB 2-way associative cache with LRU replacement. You are told the cache uses 5 bits for the offset field. Write in the number of bits in the tag and index fields. Tag length in bits = Index length in bits =Consider that we have a direct-mapped cache that uses 64-bit addresses. If each word/ block is 128 bits and there are 32K lines in the cache: (a) (3) What is the total capacity of this cache? (b) (5) How many bits are used for the tag, index, and word/block offset bits in this address?For a direct-mapped cache design with 32-bit addresses and 32-bit words (data and instructions). the following bits of the address are used to access the cache: Tag = [31:17], Index = [16:5], Offset = [4:0]. a.) What is the cache block size in 32-bit words. b.) How many blocks does the cache have? c.) What is the size of the cache in kilobytes?