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Please show solutions on how to get the 0.75 value. The circle green in the figure.   Civil engineering- steel design

Please show solutions on how to get the 0.75 value. The circle green in the figure.   Civil engineering- steel design

Structural Analysis
Structural Analysis
6th Edition
ISBN:9781337630931
Author:KASSIMALI, Aslam.
Publisher:KASSIMALI, Aslam.
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
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Please show solutions on how to get the 0.75 value. The circle green in the figure.

 

Civil engineering- steel design

 

4. Compute that tensile capacity for the double angle member shown. The bolts are 7/8-in diameter, and the steel is A36. Use standard gages. Assume that the plate does not control. -2Ls 7 x 4x2 (LLBB) @ 3 € Đ
Transcribed Image Text:4. Compute that tensile capacity for the double angle member shown. The bolts are 7/8-in diameter, and the steel is A36. Use standard gages. Assume that the plate does not control. -2Ls 7 x 4x2 (LLBB) @ 3 € Đ
Step 2: Calculations: Consider one angle and evaluate the strength: A = 7.7 in² (for one angle) A₁ = 7.7- 3.7 - 2²/1²/2+1/1×2² —— 4¹8 8 A₁ = 6.2 in² 7 (The dia of bolt is in and there are 2 holes in the angle) 8 Ae 0.75(6.2) A₂ = 4.65 in² Calculate the strength based on yielding: P=FAg n P₁ = 36x7.7 n P=277.2 kips Nominal Strength=277.2×0.9 Nominal Strength = 249.48 kips Step 3: Calculations: Calculate the strength based on fracture: P₁ = FuAe P₁ = 58×4.65 n P₁ = 269.7 kips Nominal strength = 269.7x0.75 Nominal strength = 202.275 kips The design strength in fracture is less so the safe nominal strength will be 202.275 kips For a double angle safe capacity=202.275×2 For a double angle safe capacity = 404.55 kips Solution For a double angle safe capacity is 404.55 kips
Transcribed Image Text:Step 2: Calculations: Consider one angle and evaluate the strength: A = 7.7 in² (for one angle) A₁ = 7.7- 3.7 - 2²/1²/2+1/1×2² —— 4¹8 8 A₁ = 6.2 in² 7 (The dia of bolt is in and there are 2 holes in the angle) 8 Ae 0.75(6.2) A₂ = 4.65 in² Calculate the strength based on yielding: P=FAg n P₁ = 36x7.7 n P=277.2 kips Nominal Strength=277.2×0.9 Nominal Strength = 249.48 kips Step 3: Calculations: Calculate the strength based on fracture: P₁ = FuAe P₁ = 58×4.65 n P₁ = 269.7 kips Nominal strength = 269.7x0.75 Nominal strength = 202.275 kips The design strength in fracture is less so the safe nominal strength will be 202.275 kips For a double angle safe capacity=202.275×2 For a double angle safe capacity = 404.55 kips Solution For a double angle safe capacity is 404.55 kips
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