please help- so which one is better part b has a percent yield of 76.8 percent and its melting point is what was expected also in part A but percent yield is 71.67 percent. this would be a sucess exeriment and pure? please explain
please help- so which one is better part b has a percent yield of 76.8 percent and its melting point is what was expected also in part A but percent yield is 71.67 percent. this would be a sucess exeriment and pure?
please explain
Part A
NaoH= 2.5g = 0.0625 mol
Benzaldehyde= 2.65 g =0.0250 mol
Acetone 0.725 g = 0.0125 mol
Theoretical yield=0.0125 mol
Actual yield= 2.1g
Percent yield=71.67%
Expected melting point= 110.5-112 degree Celsius
Melting point observered= 112 degree Celsius
Part B
acetophenone 0.5 g, 4.2 mmol
Para-methylbenzaldehyde 0.5 g, 4.2 mmol
NaOH=0.18g = 4.5 mol
Theroretical yield=0.93g =0.0519 mol
Percent yield=76.8%
Actual yield= 0.715 g
Melting point observered= 93 degree Celsius
Expected melting point =93-94.5 degree Celsius
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