Objectives: To determine the percent mass of acetic acid in vinegar Data: Vinegar Sample : Trial 1 Trial 2 Trial 3 No data needed Mass of flask, g No data needed Mass of flask+sample, g 5 Mass of sample, g Initial buret reading, mL 28.2 27.9 28 Final buret reading, mL Volume NaOH used, mL Concentration of NaOH, ml/L 0.09999 0.09999 0.09999 Moles of NaOH added, mol Moles of acetic acid in vinegar, mol Mass of acetic acid in vinegar, g %mass of acetic acid in vinegar, % Average % mass of acetic acid in vinegar sample Standard deviation %RSD Calculations

NaOH Concentration (M): 0.09669M   Trial 1: Inital Volume of NaOH: 0.55mL Final Volume of NaOH: 28.25 mL  Trail 2:  Intial Volume of NaOH: 18.1 mL Final Volume of NaOH: 46.1 mL   Concentration of HCl Solution Subtract the initial buret reading from the end point reading. Convert the readings to liters by dividing by 1000.     Solve this equation for the concentration of HCl:                  (CHCl)  (0.01000 liters )    =     (CNaOH)  (volume of NaOH in liters).                CNaOH is the normality of the NaOH you recorded from the bottle.       Average the two HCl concentrations.

ame: Table 2. Determination of Acetylsalicylic Acid in Aspirin. 1) Aspirin Brand (and amount of acetylsalicylic acid on label) 2) Average molar concentration of NaOH Solution B (from Part A) 3) 4) 5) 6) Mass of aspirin tablet Mass of pulverized aspirin sample Initial buret reading Final buret reading 7) Volume of NaOH Solution B added 8) Moles of NaOH 9) Moles of acetylsalicylic acid in sample 10) Mass of acetylsalicylic acid in sample 11) Amount of acetylsalicylic acid per tablet T₁ 1.264 12) Mean amount of acetylsalicylic acid per tablet 13) Standard deviation for acetylsalicylic acid per tablet 14) RSD for acetylsalicylic acid per tablet 15) Relative percent error (%) 16) Is the mean amount per tablet acceptable? (Yes or no.) 0.000153 * 180. Kg Imol T₂ √3 1.261 1-259 Seat กา Basic 8.25 mg 0.0975 M Trial 1* Trial 2 *Show all calculations related to Trial 1, standard deviation, RSD, and relative % error. Mole of NaOH (0.0975) (14.3) = 0.000139 (0.0975) (15.7) = 8.000 253 23 0.0975)…

Questions 15 through 20 pertain to the following medication formula: Here is the formula a pain and inflammation reducing ointment. Methyl salicylate (sp gr = 1.167) 60 mL Lidocaine 4% (w/w) Tween:Span mix (1:4 mix) Polypeg Base 10 g QS to 0.5 kg You receive an order to make 3 solid ounces of this product. Answer the following questions pertaining to producing 3 solid ounces of the product. 15. Volume of methyl salicylate, in milliliters. 16. Weight of lidocaine in grams. 17. Weight of Tween in milligrams. 18. Weight of Span, in milligrams. 19. Weight of Polypeg base, in grams. 20. What is the final concentration of methyl salicylate, as a percent concentration (w/w)?