Peptide decomposition is one of the key processes of digestion, where a peptide bond is broken into an acid group and an amine group. We can describe this reaction as follows: Peptide(aq) + H20(1) Sacid group(aq) + amine group(aq) If we place 1.5 mol peptide into 1.0 L water, what will be the equilibrium concentrations of all species in this reaction? Assume the K value for this reaction is 3.1 × 10-³. [peptide] = M %3D [acid group] M [amine group] M

A student ran the following reaction in the laboratory at 682 K:2HI(g) H2(g) + I2(g)When she introduced HI(g) at a pressure of 5.24 atm into a 1.00 L evacuated container, she found the equilibrium partial pressure of HI(g) to be 4.15 atm.Calculate the equilibrium constant, Kp, she obtained for this reaction.Kp =

A student ran the following reaction in the laboratory at 1097 K: 2SO3(g)2SO2(g) + O2(g) When she introduced 0.0921 moles of SO3 (g) into a 1.00 liter container, she found the equilibrium concentration of O₂ (g) to be 0.0198 M. Calculate the equilibrium constant, Kc, she obtained for this reaction. Kc =

Chapter 12 part 1 #12

3. Given the chemical reaction A(aq) + 2B(aq) → C(aq) + 3D(aq) Initially, you have 2 moles of A and 3 moles of B dissolved in a total volume of 3 L. a. X moles of A reacted, and the solution reached equilibrium. Solve for the End state in term of x b. Write down the expression of the equilibrium constant (Keq) in term of x and volume.

At 773 °C, a mixture of CO(g), H2(g), and CH3OH(g) was allowed to come to equilibrium. The concentrations were determined to be: [CO] = 0.105 M, [H2] = 0.250 M, [CH3OH] = 0.00261 M. Calculate K. for the reaction CO(g) + 2H2(g) CH3OH(g) Kc = %3D

At 503 K the equilibrium constant K. for the dissociation of N,O4, N204(g) 2 2 NO2(g) has the value K = = 40.0. Calculate the concentration of N204 left undissociated when 1.00 mol of this gas is heated to 503 K in a 10.0 L container.