Chemistry
10th Edition
ISBN: 9781305957404
Author: Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher: Cengage Learning
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- Sulfur dioxide and oxygen react to form sulfur trioxide, like this: 2 SO₂(g) + O₂(g) → 2 SO3(g) Also, a chemist finds that at a certain temperature the equilibrium mixture of sulfur dioxide, oxygen, and sulfur trioxide has the following composition: compound concentration at equilibrium SO₂ 0.78 M 0₂ SO 3 0.41 M K = [] 0.72 M Calculate the value of the equilibrium constant K for this reaction. Round your answer to 2 significant digits.arrow_forwardAt a certain temperature, the equilibrium constant K for the following reaction is 3.44 x 10°: NO, (g) + CO(g)= NO(g) + CO,(g) Use this information to complete the following table. Suppose a 50. L reaction vessel is filled with 0.81 mol of NO2 and 0.81 mol of CO. What can you say about the composition of the mixture in the vessel at equilibrium? O There will be very little NO2 and CO. x10 There will be very little NO and CO2. ? Neither of the above is true. What is the equilibrium constant for the following reaction? Round your answer to 3 significant digits. K =0 NO(g)+CO2(9) NO2(9)+CO(9) What is the equilibrium constant for the following reaction? Round your answer to 3 significant digits. = 0 K = 2 NO,(9)+2CO(9) 2 NO(9)+2CO2(9)arrow_forwardThoroughly explain and answerarrow_forward
- Phosphorus pentachloride is formed when phosphorus trichloride and chlorine react according to the following reaction. PCI, 1316) + Clare) = PCIscE) The equilibrium constant for the reaction is Kc = 54.1 at 200 °C. If 0.227 mol of phosphorus trichloride is added to 0.575 mol of chlorine in a 1.86- L reaction vessel and allowed to react at this temperature, what is the equilibrium concentration (in mol/L) of chlorine? Report your answer to THREE significant figures.arrow_forwardThe equilibrium constant, K, for the following reaction is 6.59×10-2 at 546 K. PCl5(g) PCl3(g) + Cl2(g) An equilibrium mixture of the three gases in a 6.59 L container at 546 K contains 0.254 M PCl5, 0.129 M PCl3 and 0.129 M Cl2. What will be the concentrations of the three gases once equilibrium has been reestablished, if the volume of the container is increased to 11.7 L? [PCl5] = M [PCl3] = M [Cl2] = Marrow_forward- Bromine monochloride is synthesized using the reaction Br2(g) + Cl2(g) 2 BrCl(g) Kp = 1.1 x 104 at 150 K A 209.0 L flask initially contains 1.100 kg of Br2 and 1.053 kg of Cl₂. Calculate the mass of BrCl, in in the reaction mixture at equilibrium. Assume ideal gas behavior. mass of BrCl: What is the percent yield of BrCl? percent yield: grams, that is present g %arrow_forward
- Phosphorus pentachloride decomposes according to the chemical equation PCI, (g) = PCI,(g) + Cl, (g) Ke = 1.80 at 250 °C A 0.1978 mol sample of PCl, (g) is injected into an empty 3.15 L reaction vessel held at 250 °C. Calculate the concentrations of PCI, (g) and PCI, (g) at equilibrium. [PCI,] = %3D [PCI,] = M %3D Question Source: MRG - General Chemistry | Pul terms of use | help about us careers privacy policy contact us N prime video P IIarrow_forwardPhosphorus pentachloride decomposes according to the chemical equation PCI, (g) = PCI, (g) + Cl, (g) K. 1.80 at 250 °C A 0.1952 mol sample of PCl, (g) is injected into an empty 2.15 L reaction vessel held at 250 °C. Calculate the concentrations of PCl, (g) and PCl, (g) at equilibrium. [PCI,] = M [PCI,] = Marrow_forwardCalculate the equilibrium concentrations for all reactants and products if initial concentrations of CH4 is 0.400 M, H2S is 0.800 M, CS2 is 0.400 M, H2 is 0.800 M are mixed and allowed to establish equilibrium. The Kc for the reaction is 0.0360 and the equilibrium concentration of CH4is 0.556 M. CH4(g) + 2H2S(g) ↔ CS2(g) + 4H2(g) Group of answer choices [CH4] = 0.556 M, [H2S] = 0.488 M, [CS2] = 0.556 M, [H2] = 1.42 M. [CH4] = 0.556 M, [H2S] = 1.11 M, [CS2] = 0.244 M, [H2] = 0.176 M. [CH4] = 0.556 M, [H2S] = 0.244 M, [CS2] = 0.956 M, [H2] = 1.36 M. [CH4] = 0.556 M, [H2S] = 1.11 M, [CS2] = 0.556 M, [H2] = 1.42 M.arrow_forward
- Calculating an equilibrium constant from a partial equilibrium composition Ammonia has been studied as an alternative "clean" fuel for internal combustion engines, since its reaction with oxygen produces only nitrogen and water vapor, and in the liquid form it is easily transported. An industrial chemist studying this reaction fills a 500. mL flask with 3.3 atm of ammonia gas and 0.87 atm of oxygen gas, and when the mixture has come to equilibrium measures the partial pressure of water vapor to be 1.6 atm. Calculate the pressure equilibrium constant for the combustion of ammonia at the final temperature of the mixture. Round your answer to 2 significant digits. K = 0 P ☐ x1 x10 ☑ 5arrow_forwardThe equilibrium constant, K, for the following reaction is 1.29x10-2 at 600 K. COC,(g) CO(g) + Cl2(g) + C2(g) Calculate the equilibrium concentrations of reactant and products when 0.262 moles of COCI,(g) are introduced into a 1.00 L vessel at 600 K. [COCI,] = [CO] [Ch] MMMarrow_forwardAn equilibrium mixture of PC1, (g), PC1, (g), and Cl₂ (g) has partial pressures of 217.0 Torr, 13.2 Torr, and 13.2 Torr, respectively. A quantity of Cl₂ (g) is injected into the mixture, and the total pressure jumps to 263.0 Torr at the moment of mixing. The system then re-equilibrates. The chemical equation for this reaction is PC1₂(g) + Cl₂(g) = PCl, (g) Calculate the new partial pressures, P, after equilibrium is reestablished. PPCL, Pch PPCL, = = = Torr Torr Torrarrow_forward
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