...S6.10 A process that is considered to be in control measures an ingredient in ounces. Below are the last 10 samples (each of size n = 5) taken. The population standard deviation is 1.36. pound 1 10 9 10 9 12 2 = 33900a 10 9 9 11 11 10 13 10 +0000 10 10 11 10 10 Samples 5 12 10 9 11 10 6 10 10 8 12 9 7 10 11 10 8 웅이웅이잉 13 10 8 8 10 9 8 a88229 12 12 a) What is the process standard deviation o? What is o? b) If z 3, what are the control limits for the mean chart? 10 10 12 9 8 12

...S6.10 A process that is considered to be in control measures an ingredient in ounces. Below are the last 10 samples (each of size n = 5) taken. The population standard deviation is 1.36. pound 1 10 9 10 9 12 2 = 33900a 10 9 9 11 11 10 13 10 +0000 10 10 11 10 10 Samples 5 12 10 9 11 10 6 10 10 8 12 9 7 10 11 10 8 웅이웅이잉 13 10 8 8 10 9 8 a88229 12 12 a) What is the process standard deviation o? What is o? b) If z 3, what are the control limits for the mean chart? 10 10 12 9 8 12

Practical Management Science

6th Edition

ISBN:9781337406659

Author:WINSTON, Wayne L.

Publisher:WINSTON, Wayne L.

Chapter2: Introduction To Spreadsheet Modeling

Section: Chapter Questions

Problem 20P: Julie James is opening a lemonade stand. She believes the fixed cost per week of running the stand...

See similar textbooks

Similar questions

The x-bar chart tests the change in the number of defective items in a given sample O a. TRUE O b. FALSE IS PAGE acer F2 F3 F4 F5 F6 F7 F8 Coca) F9 F10 F11 DIO 2$ 70 &
Bill Kime's bowling ball factory makes bowling balls of adult size and weight only. The standard deviation in the weight of a bowling ball produced at the factory is known to be 0.39 pounds. Each day for 24 days, the average weight, in pounds, of 9 of the bowling balls produced that day has been assessed as follows Day 1 2 3 4 5 6 Average (lb) 9.9 9.9 10.1 10.1 99 99 Day 7 8 9 10 11 12 Average (lb) Day Average (b) 13 14 15 16 17 18 10.1 10.0 10.0 10.1 10.1 10.0 9.9 10.1 10.1 10.0 10.1 10.1 Day 19 20 21 22 23 24 Average (lb) 99 10.0 10.1 9.9 10.0 10.0 a) Establish a control chart for monitoring the average weights of the bowling balls in which the upper and lower control limits are each two standard deviations from the mean What are the values of the control limits? Upper Control Limit (UCL)=b (Round your response to two decimal places)
Given a data set with μ=18 and σ=3, find the percent of data within each range: between 15 and 21 = [""] % between 12 and 24 = [""] % below 18 = [""] % between 12 and 21 = [""] %
For 100 consecutive days, a company making nutritional supplements has measured theamount of a protein the company puts into its protein bars. Each day, the company takesa sample of 6 protein bars. The average across all 600 bars was 31.232 grams. The standard deviation was 0.83291 gram. When constructing an X-bar chart, what would theupper control limit be?a. 30.2119b. 31.232c. 32.2521d. None of the above
What is the meaning of x ̅ ~ N (50, 2)? 1. The Sampling distribution is distributed normally with a mean of 50 and a standard deviation of 2 2. Sampling distribution of x is distributed normally with a mean of 2 and a standard deviation of 50 3. x is normally distributed with a mean of 50 and a standard deviation of 2 4. x-bar is normally distributed with a mean of 2 and a standard deviation of 50
What is the meaning of x ~ N (50, 20)? 1. Sampling distribution of x is distributed with a mean of 20 and a standard deviation of 50 2. x-bar is normally distributed with a mean of 20 and a standard deviation of 50 3. x is normally distributed with a mean of 50 and a standard deviation of 20 4. Sampling distribution of x is distributed with a mean of 50 and a standard deviation of 20
Five data entry operators work at the data processing department of the Birmingham Bank. Each day for 30 days, the number of defective records in a sample of 250 records typed by these operators has been noted, as follows: Sample No. 12 2 3 4 5 6 7 8 9 10 No. Defectives 8 5 18 9 18395 10 14 Sample No. 11 12 13 14 15 16 17 18 19 20 No. Defectives 7 4 a) Establish 30 upper and lower control limits. 54697496 15 10 11 19 16 Sample No. 21 222222NERS 23 24 25 26 27 28 29 30 No. Defectives 16 12 8726668 12 11 13 6, 12 UCLp = (enter your response as a number between 0 and 1; rounded to three decimal places).
According to Reader's Digest, 47% of primary care doctors think their patients receive unnecessary medical care. Use z-table. a. Suppose a sample of 310 primary care doctors was taken. Show the sampling distribution of the proportion of the doctors who think their patients receive unnecessary medical care. E(F) (to 4 decimals) b. What is the probability that the sample proportion will be within ±0.03 of the population proportion. Round your answer to four decimals. c. What is the probability that the sample proportion will be within 0.05 of the population proportion. Round your answer to four decimals. d. What would be the effect of taking a larger sample on the probabilities in parts (b) and (c)? Why? The probabilities would - Select your answer - This is because the increase in the sample size makes the standard error, Op . - Select your answer - ♥
When a robot welder is functioning properly the cylinders it produces burst (on average) at 3400 psi, with known standard deviation 100 psi. Determine the 3-Sigma mean control chart limits. Test lot sample sizes are n=4 cylinders randomly selected from the production line. a. Centerline = ____ b. Upper Limit = ____ c. Lower Limit = ____ d. What is the probability that random variation will exceed the ± 3-sigma limits ____. (four decimal places with zero before the decimal)
Refer to Table S6.1 - Factors for Computing Control Chart Limits (3 sigma) for this problem. Twelve samples, each containing five parts, were taken from a process that produces steel rods at Emmanual Kodzi's factory. The length of each rod in the samples was determined. The results were tabulated and sample means and ranges were computed. The results were: Sample Mean (in.) Range (in.) Sample Sample Sample Mean (in.) Range (in.) 1 9.404 0.044 7 9.403 0.021 2 9.402 0.051 8 9.405 0.058 3 9.393 0.042 9.395 0.039 4 9.404 0.037 10 9.401 0.038 9.399 0.048 11 9.401 0.054 9.397 0.053 12 9.404 0.061 For the given data, the x = inches (round your response to four decimal places). Based on the sampling done, the control limits for 3-sigma x chart are: Upper Control Limit (UCL;) = inches (round your response to four decimal places). Lower Control Limit (LCL;) = inches (round your response to four decimal places).
A metal fabricator produces connecting rods with an outer diameter that has a 1± 0.02 inch specification. A machine operator takes several sample measurements over time and determines the sample mean outer diameter to be 1.005 inches with a standard deviation of 0.003 inch. Calculate the process capability index for this example. Note: Round your answer to 3 decimal places. Process capability index
4. Refer to Table S6.1 - Factors for Computing Control Chart Limits (3 sigma) LOADING... for this problem. Auto pistons at Wemming Chung's plant in Shanghai are produced in a forging process, and the diameter is a critical factor that must be controlled. From sample sizes of 10 pistons produced each day, the mean and the range of this diameter have been as follows: Day Mean x (mm) Range R (mm) 1 156.9 4.4 2 155.2 4.4 3 155.6 4.3 4 153.5 4.8 5 156.6 4.7 Part 2 a) What is the value of x? x= _______ mm (round your response to two decimal places). b) What is the value of Upper R overbarR ? Upper R overbarRequals= _______ mm (round your response to two decimal places). c) What are the UCL Subscript x overbarUCLx and LCL Subscript x overbarLCLx using 3-sigma ? Upper Control Limit (UCL Subscript x overbarUCLx ) = _________ mm (round your response to two…