n a survey of 3196 adults, 1405 say they have started paying bills online in the last year. Construct a​ 99% confidence interval for the population proportion. Interpret the results.

Q: In a survey of 2591 adults in a recent​ year 1414, say they have made a New​ Year's resolution.…

A: From the provided information,Confidence level = 90% and 95%

Q: In a survey of 3001 ​adults, 1486 say they have started paying bills online in the last year.…

A: Assuming that the number of people paying bills online has a binomial distribution with n=3001, and…

Q: In a survey of 2224 adults in a recent​ year, 1280 say they have made a New​ Year's resolution.…

A: Obtain the 90% confidence interval for the population proportion. The 90% confidence interval for…

Q: In a survey of 2865 ​adults, 1413 say they have started paying bills online in the last year.…

A:

Q: survey of 2542 adults in a recent​ year, 1362 say they have made a New​ Year's resolution.…

A: From the given information we construct 90% and 95% confidence interval.

Q: ) When 415 junior college students were surveyed, 150 said they have a passport. Construct a 95%…

A:

Q: n a survey of 2558 ​adults, 1413 say they have started paying bills online in the last year.…

A: Solution: Given information: n= 2558 Sample size of adults  x = 1413 adults started paying bills…

Q: In a survey of 2274 adults, 749 say they believe in UFOs. Construct a 99% confidence interval for…

A:

Q: In a survey of 2549 adults in a recent​ year, 1270 say they have made a New​ Year's resolution.…

A:

Q: In a survey of 2195 adults in a recent​ year, 1454 say they have made a New​ Year's resolution.…

A:

Q: In a survey of 2208 adults in a recent​ year, 1438 say they have made a New​ Year's resolution.…

A: Construct 90% confidence interval for population proportion:The sample of 2,208 adults among that…

Q: In a survey of 3254 ​adults, 1433 say they have started paying bills online in the last year.…

A: Given X=1433 n=3254

Q: adults in a recent​ year, 742 made a New​ Year's resolution to eat healthier.   Construct​ 90% and​…

A: The value of z at a 90% confidence level is 1.645, which can be found by using the standard normal…

Q: In a survey of 2000 adults in a recent​ year, 708 made a New​ Year's resolution to eat healthier.…

A: Confidence interval for population proportion is given by, p^ +- z* √(pq/n) At 90% z = 1.645 At 95%…

Q: In a survey of 2113 adults in a recent​ year, 741 made a New​ Year's resolution to eat healthier.…

A:

Q: In a survey of 2703 ​adults, 1438 say they have started paying bills online in the last year.…

A: We have given that, Number of favorable cases(X) = 1438,   Sample size(n) = 2703 Sample proportion…

Q: Out of 400 people sampled, 32 had kids. Based on this, construct a 95% confidence interval for the…

A: Solution: Let X be the number of people had kids and n be the sample number of people. From the…

Q: a survey of 3447 adults, 1477 say they have started paying bills online in the last year.…

A:

Q: In a survey of 3985 ​adults, 711 oppose allowing transgender students to use the bathrooms of the…

A: Given, n=3985 x=711 To find a confidence interval for a population proportion.

Q: In a survey of 4052 ​adults, 723 oppose allowing transgender students to use the bathrooms of the…

A: It is given that x = 723 and n= 4,052.

Q: In a survey of 2282​ adults, 749 say they believe in UFOs. Construct a 90% confidence interval for…

A:

Q: In a survey of 2002 adults in a recent​ year, 701 made a New​ Year's resolution to eat healthier.…

A: Given:

Q: In a survey of 2405 adults in a recent​ year, 1217 say they have made a New Year's resolution.…

A: Given: n=2405 x=1217

Q: In a survey of 793 adults, 460 say they have started paying bills online in the last year. Construct…

A: Answer: From the given data, Sample size(n) = 793 X = 460 98% confidence interval,

Q: In a survey of 3285​ adults, 1424 say they have started paying bills online in the last year.…

A: X = 1424 N = 3285 99% Confidence level

Q: In a survey of 2542 adults in a recent​ year, 1487 say they have made a New​ Year's resolution.…

A: Given,  n = 2542 x = 1487 proportion p  = 1487/2542                       = 0.5850

Q: In a survey of 2896 adults, 1441 say they have started paying bills online in the last year.…

A: Given data X=1441 n=2896

Q: In a survey of 2552 ​adults, 1423 say they have started paying bills online in the last year.…

A: Given that, In a survey of 2552 adults, 1423 say they have started paying bills online in the last…

Q: In a survey of 2407 adults in a recent​ year,1468 say they have made a New​ Year's resolution.…

A: Given that,  Sample size, n= 2407 And X= 1468 We know that proportion, p=X/n So p= 1468/2407 p=…

Q: In a survey of 589 adults, 233 say they have started paying bills online in the last year. Construct…

A:

Q: In a survey of 2108 adults in a recent​ year, 1305 say they have made a New​ Year's resolution.…

A:

Q: In a survey of 2000 adults in a recent​ year 1404, say they have made a New​ Year's resolution.…

A: n=2000x=1404

Q: In a survey of 485 adults, 156 say they have started paying bills online in the last year. Construct…

A: Answer: From the given data, Sample size(n) = 485 X = 156 95% confidence interval,

Q: n a survey of 4026 ​adults, 708 oppose allowing transgender students to use the bathrooms of the…

A:

Q: If n=590 and p=0.93, construct a 90% confidence interval.

A: Express the expression for the confidence interval. C.I=p±Z*p(1-p)n Here, Z* is the critical value .…

Q: In a survey of 4061 ​adults, 738 say they have seen a ghost. Construct a​ 99% confidence interval…

A: In this question, it has been given that 738 people out of 4061 people have seen the ghost, we have…

Q: 324 out of a simple random sample of 400 students hated their online math course. Find a 99%…

A: Given: Number of students that hated the online math course (y) = 324 Number of students (n) = 400…

Q: a survey of 3409 adults, 1445 say they have started paying bills online in the last year.  Construct…

A: The confidence interval = 99%The faovarble cases [x] = 1445The sample size [n] = 3409

Q: In a survey of 1000 people, 850 said they would not to travel to Disney World this summer. Construct…

A: Given: n=1000 and x=850 Then,p^=xn=8501000=0.85

Q: In a survey of 3235 adults 1499 say they have started paying bills online in the last year. A 99%…

A: Solution: Let X be the number of adults say they have started paying bills online in the last year…

Q: Construct a​ 99% confidence interval for the population proportion. Interpret the results.

A:

Q: n a survey of 3932 ​adults, 718 oppose allowing transgender students to use the bathrooms of the…

A:

Q: 82 adults selected randomly from one town, 66 have health insurance. Find a 90% confidence interval…

A:

Q: In a survey of 2693 ​adults, 1495 say they have started paying bills online in the last year.…

A: Given that, In a survey of 2693 ​adults, 1495 say they have started paying bills online in the last…

Q: In a survey of 2334 adults in a recent​ year,1370 say they have made a New​ Year's resolution.…

A: Given n=2334 X=1370

Q: In a survey of 3292 adults, 1470 say they have started paying bills online in the last year.…

A: Using Excel formula “=NORM.S.INV(1-(0.01/2))”, the critical value for 99% confidence level is…

Types of Bias

Statistics is the study of data collection, organization, analysis, interpretation, and presentation. Statistical bias is a characteristic of a statistical technique or its findings in which the expected value deviates from the actual root quantitative parameter being estimated. According to the actual definition of bias, it refers to the tendency of a statistic to overestimate or underestimate a parameter.