) When 415 junior college students were surveyed, 150 said they have a passport. Construct a 95% confidence interval for the proportion of junior college students that have a passport. Round to the nearest thousandth.

Q: f n=450 and X = 360, construct a 99% confidence interval.

A:

Q: In a sample of 460 adults, 262 had children. Construct a 95% confidence interval for the true…

A: Provided information: Total number of adults = 460 and 262 had children 95% confidence level

Q: Out of 400 people sampled, 48 had kids. Based on this, construct a 95% confidence interval for the…

A: According to the given information, we have Total number of people sampled = 400 and 48 had kids.…

Q: Out of 100 people sampled, 77 had kids. Based on this, construct a 95% confidence interval for the…

A: We have to find 95% confidence interval for the true population proportion of people with kids.

Q: A survey of 700 non-fatal accidents showed that 167 involved uninsured drivers. Construct a 99%…

A: Given data,n=700x=167Point estimate isp=xn=167700=0.2386Construct a 99% confidence interval?

Q: A university dean is interested in determining the proportion of students who receive some sort of…

A: Given data, n=152 x=101 p=x/n =0.664 The 95% CI is Zc=1.96

Q: A university dean is interested in determining the proportion of students who receive some sort of…

A: It is given that Sample size n = 250 Number of students receiving scholarship, X = 70 The critical…

Q: 3. A survey of 2,950 Filipinos showed that 2,655 trust the Supreme Court decisions on legal issues.…

A: Let X be the number of trust the supreme court decision on legal issues  n be the sample size  Given…

Q: Out of 500 people sampled, 395 had kids. Based on this, construct a 90% confidence interval for the…

A: It is given that 395 out of 500 people sampled had kids. The sample proportion is 395/500 = 0.79.…

Q: A national polling organization surveyed 1000 Americans and found that 350 admitted to being guilty…

A: Given: x=350 n=1000 p^=xn=3501000=0.35

Q: Insurance companies are interested in knowing the population percent of drivers who always buckle up…

A:

Q: In a survey of 2000 adults in a recent​ year, 708 made a New​ Year's resolution to eat healthier.…

A: Confidence interval for population proportion is given by, p^ +- z* √(pq/n) At 90% z = 1.645 At 95%…

Q: Out of 400 people sampled, 240 had kids. Based on this, construct a 95% confidence interval for the…

A:

Q: Approximately 1.55 percent of people ages 40-50 have breast cancer.* Suppose a person has a 86…

A: Probability is a chance of occurrence of any event.

Q: Out of 300 people sampled, 138 had kids. Based on this, construct a 90% confidence interval for the…

A: Given data, n=300 x=138 p=x/n=138/300 =0.46 z-value at 90% confidence is Zc=1.645

Q: A medical director needs to know the proportion of patients who have a single bed in their room. A…

A: It is given that sample size (n) is 200 and p-hat value is 0.59.

Q: Define the confidence level?

A: It is the likelihood of containing the true population parameter under the confidence interval when…

Q: In a survey of 2282​ adults, 749 say they believe in UFOs. Construct a 90% confidence interval for…

A:

Q: In a survey of 2002 adults in a recent​ year, 701 made a New​ Year's resolution to eat healthier.…

A: Given:

Q: In a survey of 2004 adults in a recent​ year, 717 made a New​ Year's resolution to eat healthier.…

A:

Q: A department chair wanted to know whose students performed better on a common pass/fail final exam:…

A: p1 :  proportion of students passed in smith's  class p2 :  proportion of students passed in Jones's…

Q: Out of 100 people sampled, 35 had kids. Based on this, construct a 95% confidence interval for the…

A:

Q: In one city, 59.6% of the 1500 students surveyed said they eat at the school cafeteria. Find the 95%…

A: Given, Sample size=n=1500 p^=0.596 α=0.05

Q: Suppose a professor wants to know if students in her statistics class have a good grasp of basic…

A: Given: Sample size n=6 Sample mean x¯=∑i=1nXin=62+92+75+68+83+956=79.167 Sample standard deviation…

Q: In a sample of 110 adults, 76 had children. Construct a 95% confidence interval for the true…

A: It is given that, in a sample of 110 adults, 76 had children. It is needed to find a 95% confidence…

Q: in a survey of 2042 adults in a recent​ year, 715 made a New​ Year's resolution to eat healthier.…

A:

Q: Out of 300 people sampled, 228 had kids. Based on this, construct a 90% confidence interval for the…

A: Introduction Sample size, n=300 No. of people who had kids, x=228 CL=0.90

Q: In a survey of 2255 adults, 741 say they believe in UFOS. Construct a 95% confidence interval for…

A:

Q: A research group asked 4488 Americans how they fall asleep, and 536 of them fall asleep on their…

A: Obtain the 90% confidence interval for the percentage of all Americans who fall asleep on their…

Q: According the the U.S. Census bureau, the percentage of Santa Ana residents living in poverty is…

A: Given: p^1=0.177p^2=0.133n1=1200n2=1500

Q: When 290 college students are randomly surveyed, it is found that 120 own a car. Find a 99%…

A: Given that, x=120,n=290 The sample proportion is, Critical values: By using the standard normal…

Q: In a sample of 310 adults, 177 had children. Construct a 87% confidence interval for the true…

A: Find z-critical value:…

Q: A random sample of 2000 car owners in a particular city found 740 car owners who received a speeding…

A:

Q: To assess the proportion of the readers of a magazine being professional, a random sample of 1000…

A: Given that the random sample of 1000 readers is selected and 660 are found to be professionals. That…

Q: In a survey of 2270 adults, 715 say they believe in UFOS. Construct a 95% confidence interval for…

A: x = 715 n = 2270

Q: A survey of 127 patients in a particular hospital determined that 54% of them felt that they were…

A: The sample proportion of patients felt they were receiving excellent care (p-cap) is 0.54. The…

Q: Out of 300 people sampled, 24 had kids. Based on this, construct a 95% confidence interval for the…

A:

Q: A researcher wanted to compare the percentages of men and women who play the lottery.  They randomly…

A:

Q: In a survey of 2268 adults, 709 say they believe in UFOS. Construct a 99% confidence interval for…

A: According to the given information, we have Total number of adults in a survey = 2268 709 say they…

Q: In a survey of 2291 adults, 743 say they believe in UFOs. Construct a 99% confidence interval for…

A: sample size(n)=2291No. of adults say they believe in UFOs(x)=743

Q: In a survey of 2286 ​adults, 745 say they believe in UFOs.   Construct a 90% confidence interval for…

A: Proportion is almost similar to the concept of probability. Proportion is a fraction of population…

Q: A marketing survey involves product recognition in New York and California. Of 558 New Yorkers…

A:

Q: In a survey of 2013 adults in a recent​ year, 731 made a New​ Year's resolution to eat healthier.…

A:

Q: Find 90% confidence interval for the true proportion of all medical students who plan to work in a…

A: Given : Sample Size, n = 300 Number of successes, x = 30

2-Proportion Test

In a 2-proportion test, two separate proportions are measured at the same time, and their similarity is evaluated. It is also known as a 2-proportion z-test, and a comparison of two different proportions is done in this method.