Answered: In a survey of 3071 adults, 1484 say they have started paying bills online in the last year. Construct a 99% confidence interval for the population…

MATLAB: An Introduction with Applications

6th Edition

ISBN: 9781119256830

Author: Amos Gilat

Publisher: John Wiley & Sons Inc

See similar textbooks

Related questions

Q: In a survey of 3001 adults, 1486 say they have started paying bills online in the last year.…

A: Assuming that the number of people paying bills online has a binomial distribution with n=3001, and…

Q: In a survey of 2865 adults, 1413 say they have started paying bills online in the last year.…

Q: A survey of 120 female freshmen showed that 9 did not wish to work after marriage. Find the 99%…

Q: n a survey of 2558 adults, 1413 say they have started paying bills online in the last year.…

A: Solution: Given information: n= 2558 Sample size of adults x = 1413 adults started paying bills…

Q: A survey of 700 non-fatal accidents showed that 167 involved uninsured drivers. Construct a 99%…

A: Given data,n=700x=167Point estimate isp=xn=167700=0.2386Construct a 99% confidence interval?

Q: In a survey of 3254 adults, 1433 say they have started paying bills online in the last year.…

A: Given X=1433 n=3254

Q: In a survey of 3478 adults, 1462 say they have started paying bills online in the last year.…

A: From the provided information,Confidence level = 99%

Q: In a survey of 2000 adults in a recent year, 708 made a New Year's resolution to eat healthier.…

A: Confidence interval for population proportion is given by, p^ +- z* √(pq/n) At 90% z = 1.645 At 95%…

Q: In a survey of 2703 adults, 1438 say they have started paying bills online in the last year.…

A: We have given that, Number of favorable cases(X) = 1438, Sample size(n) = 2703 Sample proportion…

Q: Out of 400 people sampled, 32 had kids. Based on this, construct a 95% confidence interval for the…

A: Solution: Let X be the number of people had kids and n be the sample number of people. From the…

Q: a survey of 3447 adults, 1477 say they have started paying bills online in the last year.…

Q: confidence interval for the proportion of unemployed adults who have been unemployed for more than…

A: Here given In a survey of 532 unemployed adults, 225 said that they had been unemployed for more…

Q: In a survey of 3185 adults, 1455 say they have started paying bills online in the last year.…

Q: In a survey of 2002 adults in a recent year, 701 made a New Year's resolution to eat healthier.…

A: Given:

Q: In a study of 120 randomly selected families, 50 said they streamed their television content. Find…

Q: In a survey of 2004 adults in a recent year, 717 made a New Year's resolution to eat healthier.…

Q: In a survey of 793 adults, 460 say they have started paying bills online in the last year. Construct…

A: Answer: From the given data, Sample size(n) = 793 X = 460 98% confidence interval,

Q: In a survey of 2896 adults, 1441 say they have started paying bills online in the last year.…

A: Given data X=1441 n=2896

Q: In a sample of 110 adults, 76 had children. Construct a 95% confidence interval for the true…

A: It is given that, in a sample of 110 adults, 76 had children. It is needed to find a 95% confidence…

Q: in a survey of 2042 adults in a recent year, 715 made a New Year's resolution to eat healthier.…

Q: In a survey of 2552 adults, 1423 say they have started paying bills online in the last year.…

A: Given that, In a survey of 2552 adults, 1423 say they have started paying bills online in the last…

Q: In a survey of 26582658 adults, 14961496 say they have started paying bills online in the last…

A: The objective of this question is to construct a 99% confidence interval for the population…

Q: In a survey of 589 adults, 233 say they have started paying bills online in the last year. Construct…

Q: 324 out of a simple random sample of 400 students hated their online math course. Find a 99%…

A: Given: Number of students that hated the online math course (y) = 324 Number of students (n) = 400…

Q: a survey of 3409 adults, 1445 say they have started paying bills online in the last year. Construct…

A: The confidence interval = 99%The faovarble cases [x] = 1445The sample size [n] = 3409

Q: In a survey of 3235 adults 1499 say they have started paying bills online in the last year. A 99%…

A: Solution: Let X be the number of adults say they have started paying bills online in the last year…

Q: Construct a 99% confidence interval for the population proportion. Interpret the results.

Q: Out of 100 people sampled, 44 have lied to a family member in the past month. Based on this,…

Q: In a survey of 2646 adults, 1401 say they have started paying bills online in the last year.…

A: Number of adults (n) = 2646 Number of adults who say they have started paying bills online in the…

Q: In a survey of 3342 adults, 1489 say they have started paying bills online in the last year.…

A: Given Information: To construct a 99% confidence interval for the population proportion and…

Q: In a survey of 2013 adults in a recent year, 731 made a New Year's resolution to eat healthier.…

Q: In a survey of 3426 adults, 1487 say they have started paying bills online in the last year.…

A: From the provided information, Sample size (n) = 3426 Out of which 1487 say they have started paying…

Q: 700 randomly selected Americans were asked if they believed the minimum wage should be raised. 350…

A: Given that p = 700 x = 350 Confidence level(c) = 90% = 0.90 Significance level (α) = 1-c = 1-0.90=…

Q: In a random sample of 230 men , 18 or older , 142 were married. Construct and explain a 90%…

A: Solution: Let X be the number of married men 18 or older and n be the sample number of men. From the…

Q: Out of 100 people sampled, 54 had kids. Based on this, construct a 90 % confidence interval for the…

Q: In a sample of 480 adults, 384 had children. Construct a 99% confidence interval for the true…

A: The random variable adults with children follow normal distribution. We have to construct 99%…

Q: Of 848 children surveyed, 144 plan to join a volunteer group in the future. Construct a 90%…

A: We have given that n=848, X=144, C.I=90%=0.90

Q: A survey conducted by the U.S. department of Labor found the 48 out of 500 heads of households were…

A: Given that, n = 500 x = 48 90% confidence interval

Q: Compute the probability of successfully completing the task for an engineer having 24 months of…

A: Given the data of monthly experience of the task is a success or not for 2 engineers as shown below…

Q: A Gallup poll of 1487 adults showed that 43% of the respondents have Facebook pages. Construct a…

A: Confidence Interval: In statistics, we can say a range of values of the specified population…

Q: According to a study, 1156 out of 7730 adults said that they would ask their siblings first in case…

A: Obtain the 90% percent confidence interval for the proportion of adults said that they would ask…

Q: In a random sample of 230 men, 18 or older, 142 are married. Construct and explain a 98% confidence…

A: Given Data Sample Size, n = 230 Number of successes, x = 142.0 Significance level,…

Q: In a survey of 3038 adults, 1448 say they have started paying bills online in the last year.…

A: Confidence Interval:The form of the confidence interval is,CI = Point estimate ± Margin of error.The…

Topic Video

Question

In a survey of

3071

adults,

1484

say they have started paying bills online in the last year.

Construct a 99% confidence interval for the population proportion. Interpret the results.

Expert Solution

This question has been solved!

Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.

See solution Check out a sample Q&A here

Step 1

VIEW

Step 2

VIEW

Step by stepSolved in 2 steps with 3 images

See solution

Check out a sample Q&A here

Knowledge Booster

$Statistics$

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, statistics and related others by exploring similar questions and additional content below.

In a survey of 3071 ​adults, 1484 say they have started paying bills online in the last year. Construct a​ 99% confidence interval for the population proportion. Interpret the results.

Related questions

In a survey of 3071 adults, 1484 say they have started paying bills online in the last year. Construct a 99% confidence interval for the population proportion. Interpret the results.