Mutation analysis of GCK gene in patients with diabetes revealed a c.114 T→A (shown in bold and underlined) substitution in heterozygote state. In order to check the mutation in healthy individuals, restriction enzyme analysis will be used. a) Which enzyme can we use to differentiate wild type and mutant sequence? Please indicate which allele (wild type or mutant allele) will be cut with the restriction enzyme. Use table 1 shown below. b) Draw the expected agarose gel result of a homozygous wild type, homozygous mutant and heterozygote individual after restriction enzyme analysis. ATGAGGCTCTTTGCCACCAGTCCCAGTTTTATGCATGGCAGCTCTAATGACAGGATGGTCACCCCTGCTGAGGCC ACTCCTGGTCACCATGACAACCACAGGCCCTCTCAGTATCACAGTAAGCCCTGGCAGGAGAATCCCCCACTCCAC ACCTGGCTGGAGCACGAAATGCCGAGCGGCGCCTGAGCCCCAGGGAAGCAGGCTAGGATGTGA Figure 1. GCK gene sequence. Length of the fragment is 213bp. Table1. The restriction enzymes and their recognition sequences. Restriction enzyme Recognition seguence www wwwtw ww Nar I GG/CGCC Dde I C/TNAG Hae II NGCGC/n Hpall Cc/GG Alul AG/CT Smal CCC/GGG Mbol /GATC Mae III /GTNAC Bsp 1286 I GnGCn/C Hind II A/AGCTT wwwm EcoR I G/AATTC n: any nucleotide 田

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Mutation analysis of GCK gene in patients with diabetes revealed a c.114 T→A (shown in bold and
underlined) substitution in heterozygote state. In order to check the mutation in healthy individuals,
restriction enzyme analysis will be used.
a) Which enzyme can we use to differentiate wild type and mutant sequence? Please indicate which
allele (wild type or mutant allele) will be cut with the restriction enzyme. Use table 1 shown below.
b) Draw the expected agarose gel result of a homozygous wild type, homozygous mutant and
heterozygote individual after restriction enzyme analysis.
ATGAGGCTCTTTGCCACCAGTCCCAGTTTTATGCATGGCAGCTCTAATGACAGGATGGTCACCCCTGCTGAGGCC
ACTCCTGGTCACCATGACAACCACAGGCCCTCTCAGTATCACAGTAAGCCCTGGCAGGAGAATCCCCCACTCCAC
ACCTGGCTGGAGCACGAAATGCCGAGCGGCGCCTGAGCCCCAGGGAAGCAGGCTAGGATGTGA
Figure 1. GCK gene sequence. Length of the fragment is 213bp.
Table1. The restriction enzymes and their recognition sequences.
Restriction enzyme
Recognition seguence
www
wwwtw ww
Nar I
GG/CGCC
Dde I
C/TNAG
Hae II
NGCGC/n
Hpall
Cc/GG
Alul
AG/CT
Smal
CCC/GGG
Mbol
/GATC
Mae III
/GTNAC
Bsp 1286 I
GnGCn/C
Hind II
A/AGCTT
EcoR I
G/AATTC
n: any nucleotide
/: cutting site
田
Transcribed Image Text:Mutation analysis of GCK gene in patients with diabetes revealed a c.114 T→A (shown in bold and underlined) substitution in heterozygote state. In order to check the mutation in healthy individuals, restriction enzyme analysis will be used. a) Which enzyme can we use to differentiate wild type and mutant sequence? Please indicate which allele (wild type or mutant allele) will be cut with the restriction enzyme. Use table 1 shown below. b) Draw the expected agarose gel result of a homozygous wild type, homozygous mutant and heterozygote individual after restriction enzyme analysis. ATGAGGCTCTTTGCCACCAGTCCCAGTTTTATGCATGGCAGCTCTAATGACAGGATGGTCACCCCTGCTGAGGCC ACTCCTGGTCACCATGACAACCACAGGCCCTCTCAGTATCACAGTAAGCCCTGGCAGGAGAATCCCCCACTCCAC ACCTGGCTGGAGCACGAAATGCCGAGCGGCGCCTGAGCCCCAGGGAAGCAGGCTAGGATGTGA Figure 1. GCK gene sequence. Length of the fragment is 213bp. Table1. The restriction enzymes and their recognition sequences. Restriction enzyme Recognition seguence www wwwtw ww Nar I GG/CGCC Dde I C/TNAG Hae II NGCGC/n Hpall Cc/GG Alul AG/CT Smal CCC/GGG Mbol /GATC Mae III /GTNAC Bsp 1286 I GnGCn/C Hind II A/AGCTT EcoR I G/AATTC n: any nucleotide /: cutting site 田
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