Kinetics and Equilibrium Calculating an equilibrium constant from a heterogeneous equilibrium... Try Again Try again... Bis 2/5 Your answer is wrong. In addition to checking your math, check that you used the right data and DID NOT round any intermediate calculations. Fluoride anion and hydronium cation react to form hydrofluoric acid and water, like this: F (aq)+H3O (aq)→HF (aq) + H2O(l) At a certain temperature, a chemist finds that a 9.9 L reaction vessel containing an aqueous solution of fluoride anion, hydronium cation, hydrofluoric acid, and water at equilibrium has the following composition: compound amount F 0.146 g H₂O 0.364 g HF 4.96 g 892. g H₂O Calculate the value of the equilibrium constant K for this reaction. Round your answer to 2 significant digits. K 8.4 x 10 C

Introductory Chemistry: A Foundation
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Author:Steven S. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Donald J. DeCoste
Chapter17: Equilibrium
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Problem 10CR: . Explain what it means that a reaction has reached a state of chemical equilibrium. Explain why...
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Kinetics and Equilibrium
Calculating an equilibrium constant from a heterogeneous equilibrium...
Try Again
Try again...
Bis
2/5
Your answer is wrong. In addition to checking your math, check that you used the right data and DID NOT round any intermediate calculations.
Fluoride anion and hydronium cation react to form hydrofluoric acid and water, like this:
F (aq)+H3O (aq)→HF (aq) + H2O(l)
At a certain temperature, a chemist finds that a 9.9 L reaction vessel containing an aqueous solution of fluoride anion, hydronium cation, hydrofluoric acid, and
water at equilibrium has the following composition:
compound amount
F
0.146 g
H₂O
0.364 g
HF
4.96 g
892. g
H₂O
Calculate the value of the equilibrium constant K for this reaction. Round your answer to 2 significant digits.
K
8.4 x 10
C
Transcribed Image Text:Kinetics and Equilibrium Calculating an equilibrium constant from a heterogeneous equilibrium... Try Again Try again... Bis 2/5 Your answer is wrong. In addition to checking your math, check that you used the right data and DID NOT round any intermediate calculations. Fluoride anion and hydronium cation react to form hydrofluoric acid and water, like this: F (aq)+H3O (aq)→HF (aq) + H2O(l) At a certain temperature, a chemist finds that a 9.9 L reaction vessel containing an aqueous solution of fluoride anion, hydronium cation, hydrofluoric acid, and water at equilibrium has the following composition: compound amount F 0.146 g H₂O 0.364 g HF 4.96 g 892. g H₂O Calculate the value of the equilibrium constant K for this reaction. Round your answer to 2 significant digits. K 8.4 x 10 C
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