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- #9. Use the information provided below to find out the molecular formula and structure of the compound. QE-300 CDCl3 al Relative Intensity 100 80 60 40 20 +0 0-min 10 3454 #1 3456 57 2907 15 2944 20 2910 36 2879 50 TO ALLE 1 In 20 30 2716 81 2001 04 2438 1 2154 84 1991 84 1972 77 1733 4 1476 23 1470 25 1447 19 1421 16 1116 25 1160 9 40 50 1306 1270 1140 1022 9 974 27 657 25 76466 6 $ 60 m/z MENYERL 70 722 27 608 13 1900 80 90 100 110 120The mass spectrum of an alkene, C8H16, exhibits a peak at m/z = 41. Draw two isomers that are consistent with these data.You measured the carbon-carbon bond lengths of four different compounds in Experiment 8 (Molecular Modeling and IR spectroscopy). Which of the following compounds has the shortest average C-C bond length? Benzene Cyclohexene Cyclohexane O Cyclohexadiene Which of the following statement(s) is(are) true? Select all that apply: When two atoms are bonded together, the distance between atoms is the same all the time. In the IR spectrum, carbonyl groups (C=O) have strong sharp peaks ranging from 1700 cm 1 to 1750 cm-1. When a molecule absorbs an IR radiation, electrons are excited within the molecule and each absorbed electron creates a band in the molecules IR spectrum. IR spectroscopy is useful in confirming the structure of the analyzed compound. Molecule N2 does not absorb IR radiation
- Но LIGH + Cv (NO3)3 911₂0 ㅋ HH₂0, 120°C32904 24h ount B Used 0.839) - terephthalic and 09 Used 2,0g - Cr (103) 3 9H₂0Analyze the mass spect (including fragmentations) for the molecular structure of vanillin (C8H8O3). M=152Calculate delta Ho for the rxn: Na2O (s) + SO3 (g) --> Na2SO4 (g) given the ff information: 1. Na (s) + H2O (l) --> NaOH (s) + 1/2 H2 (g) delta Ho = -146 kJ 2. Na2SO4 (s) + H2O --> 2NaOH (s) + SO3 (g) delta Ho = +418 kJ 3. 2Na2O (s) + 2H2 (g) --> 4Na (s) + 2H2O (l) delta Ho = +259 kJ The answer should be -581 kJ. I am very confused. thank you.
- Which of the following molecules is represented in this IR spectrum? INFRARED SPECTRUM TRANSMITTANCE 0.8 000 0 ABCD 0.6 0.4 0.2 3000 Wavenumber (cm-1) NIST Chemistry WebBook (http://webbook.nist.gov/chemistry) A B 2000 -NH₂ CH3 OH с 1000 A при OHWhy do aldehydes, esters, and amides all have a strong absorption in the 1630-1780 cm1 region of their IR spectra? A) The bond between H and the sp³-hybridized C in these functional groups vibrates in this energy range. B) Each of these functional groups has at least two resonance structures, and the different vibrations of the resonance structures give off energy in this region. C) The bond between O and the sp²-hybridized C in these functional groups vibrates at a frequency in this energy range. D) Light at this wavenumber causes the average C to O bond length to increase which causes more of this light to be transmitted. E) An electron in the bond of these functional groups gets excited to the * orbital.Molecular Recognition (Supramolecular Chemistry) in organic chemistry deals with the "lock and key " mechanisms that form new molecules. However, little is known of this subject when moleules go beyond 1500 daltons (g/mole) for example macromolecules of polyolefins (polyethylene, polypropylene), thermoplastic polyesters and polyamides (nylon). It is understood that pre-directional H bonding is the mechanism of molecular recognition of macromolecules. Question: What is the immediate and post manifestation of inducing molecular recognition to condensation polymers and ring opening polymerization polymers like thermoplastic polyesters (PET ), and Nylon 66, 6 etc. (polyamides)?
- What structural features of Hydroxypropyl Acrylate (HPA) allow it to be detected by HPLC?5. Hence show that: OU (hv exp(-ẞhv)) hv exp(-2ẞhv) =-3Nhv + oß (1-exp(-ßhv)) (1-exp(-ẞhv)) Hint 1: you will need to use the quotient rule: yf'(x) xf'(y) f'(x) f'(y) (f'(y))² (f'(y))² Hint 2: the following identity will avoid you having to use the chain rule: d (1 − e√(x)) = − f'(x)e√(x) dxHalogenated compounds are particularly easy to identify by their mass spectra because both chlorine and bromine occur naturally as mixtures of two abundant isotopes. Recall that chlorine occurs as 35Cl (75.8%) and 37Cl (24.2%); and bromine occurs as 79Br (50.7%) and 81Br (49.3%). At what masses do the molecular ions occur for the following formulas? What are the relative percentages of each molecular ion? (a) Bromomethane, CH3Br (b) 1-Chlorohexane, C6H13Cl
