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Kindly follow the 4-step rule. Use the picture as your reference and guide to solve the circuit.

Kindly follow the 4-step rule. Use the picture as your reference and guide to solve the circuit.

Introductory Circuit Analysis (13th Edition)
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...
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Kindly follow the 4-step rule.  Use the picture as your reference and guide to solve the circuit.

LEARNING EXAMPLE Write the mesh equations 3. Write equations for coupled inductors 1,-1 1,-13 V = joL (I, -1,)+ j@M(I, -I,) V2 = j@M (I, -1,)+ j@L,(I, -1,) R1 R joM jul2 V, 4. Replace into loop equations and rearrange terms RA 1 V =| R + j@L + R3 1 I,- joMI, joc, 1. Define variables for coupled inductors jol - joM + 2. Write loop equations in terms of coupled inductor voltages 1 0=- joL - joM + j@C, I,-1, V = R,I, +V + joc, -V + R,I, +V2 + R;(I, -I,)+'2-4=0 jaC 1 + joL, - jaM +R2 - j@M + j@L, +R3 + joC, %3D I3 + R,I3 + R;(I3 -1,)=0 j@C, -(-joM + jøL,+ R; )I3 0=-joMI, -(joL, - joM + R,)I, -V2 + 1 +R¸+R ]I3 joC, + jol, + GEAUX
Transcribed Image Text:LEARNING EXAMPLE Write the mesh equations 3. Write equations for coupled inductors 1,-1 1,-13 V = joL (I, -1,)+ j@M(I, -I,) V2 = j@M (I, -1,)+ j@L,(I, -1,) R1 R joM jul2 V, 4. Replace into loop equations and rearrange terms RA 1 V =| R + j@L + R3 1 I,- joMI, joc, 1. Define variables for coupled inductors jol - joM + 2. Write loop equations in terms of coupled inductor voltages 1 0=- joL - joM + j@C, I,-1, V = R,I, +V + joc, -V + R,I, +V2 + R;(I, -I,)+'2-4=0 jaC 1 + joL, - jaM +R2 - j@M + j@L, +R3 + joC, %3D I3 + R,I3 + R;(I3 -1,)=0 j@C, -(-joM + jøL,+ R; )I3 0=-joMI, -(joL, - joM + R,)I, -V2 + 1 +R¸+R ]I3 joC, + jol, + GEAUX
1 joC2 =-j8 =4 R1=1 joM =j5 j2 = joL1 joL2 =j6 3/0 = v (+ I3 R4=9 1 -3j= R3=7
Transcribed Image Text:1 joC2 =-j8 =4 R1=1 joM =j5 j2 = joL1 joL2 =j6 3/0 = v (+ I3 R4=9 1 -3j= R3=7
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