It is possible to genetically alter sexual behavior in Drosophila True False Question 5 The Cycle gene, inhibits the transcription of Period O True False
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- Polarity of oocyte of DrosophilaWhat are the cells surrounding the oocyte? Are they germ-line or somatic in origin?D Question 5 HAT48 is a histone acetyltransferase that binds DNA next to the promoter of the OVU3 gene. Likely, HAT48 leads to: O increased DNA methylation of the OVU promoter and decreased expression O closed chromatin and OVU expression O increased splicing efficiency of the primary OVU transcript and altenative splicing activation of an enhancer that represses OVU expression O open chromatin and OVU expressionhpo (hippo) mutant clones the corresponding WT twin spots were generated during Drosophila eye development, determine whether the following statements are true or false: hpo mutant clones will be larger than twin spots with larger cells hpo mutant clones will be larger than twin spots with more cells hpo mutant clones will be smaller than twin spots with smaller cells hpo mutant clones will be larger than twin spots with high levels of phosphorylated Yki
- Polarity of oocyte of DrosophilaWhat is the difference between the anterior and posterior determinant for the oocyte?Question Amuda oel and a san cel both cartan the same 46 chromosomes, but express d fferent genes. In terms of general (basal) transcription factors and activators, how do these cells differ? O Bah al trpes cartan the ame gereral tarocrpton factors and the same regulatory actirators. sh cel poes tortan the same gerverd trarecrpton factors bưt dfferent regulatory activators. O The tao tel tpes cartain dherert geeral transcrotion factors, and different reguatory activators.Preview File Edit View Go Tools Window Help )) 100% Thu Apr 29 10:44 PM A BI-201 Syllabus Virtual Spring 2021.pdf (page 1 of 19) A BioLab Fly_Group_F.pdf (page 1 of 4) Q Search DOCX v BioLab Fly Group_F.pdf HIST111 signment1 Mutation: Lobe eye shape P generation Phenotypes: Normal Lobe DOCX _female X male W1 - Puffins F. generation Phenotype Females Males Total Ratio Normal 8. 8. Lobe Screen Shot 021-04..3.03 AM F, XF, Phenotypes: Normal Normal female X male DOCX F2 generation HIST111 Phenotvoe Females Males Total Ratio Normal 6 6 Lobe 2 2 F. Punnett square F2 Punnett square DOCX HIST111 2 2 Atomic This mutation is inherited as: uctur...pdf .pdf dominant autosomal (da) recessive autosomal (ra) DOCX recessive sex-linked (rs) History homework4 APR 29 X FENE
- 9-10. The IGF2 gene is matemally imprinted, i.e., the matemal copy is not expressed. Expression of the paternal copy is enabled by methylation of a CpG island located between IGF2 and its enhancer. CTCF Maternal igr2 오오오 allele not Enhancer- transcribed Insulator Paternal ig12 9. If you isolated DNA from 20 individual spematozoa, you would expect that: Enhancer allele transcribed a. This CpG island will be methylated in about 10 of them b. This CpG island will be unmethylated in all of them c. This CpG island will be methylated in all of them d. Each sperm will carry one methylated and one unmethylated copy of this CpG island e. None of the above are trueWhich of the following proteins is a combinatorial transcriptional regulator in Drosophila that affects the differentiation of multiple cell types? O the glucocorticoid receptor O MyoD O Ey O Muts O maintenance methyltransferaseDevelopment of the nematode Caenorhabditis ele-gans generates exactly 959 somatic cells; it also producesan additional 131 cells that are later eliminated by apop-tosis. Classical genetic experiments in C. elegans isolatedmutants that led to the identification of the first genesinvolved in apoptosis. Of the many mutations affectingapoptosis in the nematode, none have ever been found inthe gene for cytochrome c. Why do you suppose that sucha central effector molecule in apoptosis was not found inthe many genetic screens for “death” genes that have beencarried out in C. elegans?
- In the following study, the investigators wanted to determine the role of cyclin B in controlling the cell cycle. Earlier researchers had found that extracts made from frog eggs (Xenopus) contained all the necessary proteins and machinery required for DNA replication. This included proteins that regulated the mitosis promoting factor (MPF). At the time of this study, cyclin B was show to affect MPF activity and the research group wanted to test using Xenopus egg extract in an assay. In Figure 1 (a) MPF activity was tested for its ability to phosphorylate Histone (H1) in sperm chromatin over a certain period of time. Additionally, the cyclin B concentration in the extract was measured. In Figure1c, Only cyclin B MRNA was added back to the RNase-treated extract and the assay was continued. What would Figure 1c seem to suggest to the authors?Concerning the Tools of Genetics Box Analysis ofCell-Cycle Mutants in Yeast:a. Describe how you would use replica plating ofmutagenized, haploid yeast cells to identifytemperature-sensitive (ts) mutations in essentialgenes needed for yeast growth and survival.b. Among the many ts mutations you found in part(a), how would you distinguish mutations in genesneeded for cell-cycle progression from those ingenes needed for other aspects of the life of yeasts?c. If you had a large collection of yeast cell-cyclemutants, how would you determine which of themutations are in the same gene and which are indifferent genes?Researchers know that Fru-M controls male sexualbehavior in Drosophila because inappropriate Fru-Mexpression in females causes them to behave likemales: Such females display male behaviors that areoriented toward other females.a. Describe a fru mutation that could cause the expression of Fru-M in females.b. Describe a transgene construct that scientistscould generate and insert into Drosophila femalesthat would have the same effect as the mutant youdescribed in (a).