Database System Concepts
7th Edition
ISBN: 9780078022159
Author: Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher: McGraw-Hill Education
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- #ifndef LLCP_INT_H#define LLCP_INT_H #include <iostream> struct Node{ int data; Node *link;};void DelOddCopEven(Node*& headPtr);int FindListLength(Node* headPtr);bool IsSortedUp(Node* headPtr);void InsertAsHead(Node*& headPtr, int value);void InsertAsTail(Node*& headPtr, int value);void InsertSortedUp(Node*& headPtr, int value);bool DelFirstTargetNode(Node*& headPtr, int target);bool DelNodeBefore1stMatch(Node*& headPtr, int target);void ShowAll(std::ostream& outs, Node* headPtr);void FindMinMax(Node* headPtr, int& minValue, int& maxValue);double FindAverage(Node* headPtr);void ListClear(Node*& headPtr, int noMsg = 0); // prototype of DelOddCopEven of Assignment 5 Part 1 #endifarrow_forwardstruct insert_at_back_of_sll { // Function takes a constant Book as a parameter, inserts that book at the // back of a singly linked list, and returns nothing. void operator()(const Book& book) { /// TO-DO (3) /// // Write the lines of code to insert "book" at the back of "my_sll". Since // the SLL has no size() function and no tail pointer, you must walk the // list looking for the last node. // // HINT: Do not attempt to insert after "my_sll.end()". // ///// END-T0-DO (3) ||||// } std::forward_list& my_sll; };arrow_forwardint tryMe(int x[], int size); void main() { int list[75]; cout<< tryMe (list, 75); } valid invalidarrow_forward
- // FILL IN THE BLANKS (LINKED-LISTS CODE) (C++)#include<iostream>using namespace std; struct ________ {int data ;struct node *next; }; node *head = ________;node *createNode() { // allocate a memorynode __________;temp = new node ;return _______ ;} void insertNode(){node *temp, *traverse;int n;cout<< "Enter -1 to end "<<endl;cout<< "Enter the values to be added in list"<<endl;cin>>n; while(n!=-1){temp = createNode(); // allocate memorytemp->data = ________;temp->next = ________;if ( ___________ == NULL){head = _________;} else {traverse = ( );while (traverse->next != ________{traverse = traverse-> ___________;} traverse->next= temp;} cout<<"Enter the value to be added in the list"<<endl;cin>>n; }} void printlist(){node *traverse = head; // if head == NULLwhile (traverse != NULL) { cout<<traverse->data<<" ";traverse = traverse->next;}} int main(){int option; do{cout<<"\n =============== MAIN…arrow_forwardinitial c++ file/starter code: #include <vector>#include <iostream>#include <algorithm> using namespace std; // The puzzle will always have exactly 20 columnsconst int numCols = 20; // Searches the entire puzzle, but may use helper functions to implement logicvoid searchPuzzle(const char puzzle[][numCols], const string wordBank[],vector <string> &discovered, int numRows, int numWords); // Printer function that outputs a vectorvoid printVector(const vector <string> &v);// Example of one potential helper function.// bool searchPuzzleToTheRight(const char puzzle[][numCols], const string &word,// int rowStart, int colStart) int main(){int numRows, numWords; // grab the array row dimension and amount of wordscin >> numRows >> numWords;// declare a 2D arraychar puzzle[numRows][numCols];// TODO: fill the 2D array via input// read the puzzle in from the input file using cin // create a 1D array for wodsstring wordBank[numWords];// TODO:…arrow_forward#include <iostream>#include <list>#include <string>#include <cstdlib>using namespace std;int main(){int myints[] = {};list<int> l, l1 (myints, myints + sizeof(myints) / sizeof(int));list<int>::iterator it;int choice, item;while (1){cout<<"\n---------------------"<<endl;cout<<"***List Implementation***"<<endl;cout<<"\n---------------------"<<endl;cout<<"1.Insert Element at the Front"<<endl;cout<<"2.Insert Element at the End"<<endl;cout<<"3.Front Element of List"<<endl;cout<<"4.Last Element of the List"<<endl;cout<<"5.Size of the List"<<endl;cout<<"6.Display Forward List"<<endl;cout<<"7.Exit"<<endl;cout<<"Enter your Choice: ";cin>>choice;switch(choice){case 1:cout<<"Enter value to be inserted at the front: ";cin>>item;l.push_front(item);break;case 2:cout<<"Enter value to be inserted at the end:…arrow_forward
- complete the //TODOs #include<iostream> #include "swap.h" using namespace std; int main(int argc, char const *argv[]) { intfoo[5] = {1, 2, 3, 4, 5}; cout<<"Addresses of elements:"<<endl; //TODO Print the addresses of array elements cout<<endl; cout<<"Elements:"<<endl;; //TODO Print all the elements using pointers cout<<endl; inta,b; intf; intflag = 1; while(flag == 1){ cout<<"Enter indices of elements you want to swap?"<<endl; cout<<"First index"<<endl; cin>>a; cout<<"Second index"<<endl; cin>>b; cout<<"Enter 0 for pass-by-value, 1 for pass-by-pointer"<<endl; cin>>f; switch (f) { case0: // Pass by Value // Compare the resultant array with the array you get after passing by pointer cout<<"Before swapping"<<endl; for(inti = 0;i<5;i++){ cout<<foo[i]<<" "; } cout<<endl; swap(foo[a],foo[b]); cout<<"\nAfter swapping"<<endl;…arrow_forwardThe mapped list pattern Our second pattern is the mapped list pattern, described in video 4 3 mapped list pattern. Often we need to write a function that takes a list as a parameter and returns a new list in which each item in the original list is "mapped" to a new item in the result list. For example, the following function takes a list of numbers as a parameter and returns a list of all the numbers squared, e.g. squares ( [1, 3, 7]) returns [1, 9, 49]. def squares (nums): "Returns the squares of the given numbers""" result = [] for num in nums: result.append (num * num) return result Although this is just a special case of the accumulator pattern, it is so common that we give it its own name: the mapped list pattern. Consider the following function: def squares(nums): ""Returns the squares of the given numbers""" result = [] for num in nums: result.append (num * num) return result If the main program calls print(squares ( [5, -3, 2, 7]) what is the state table for the function…arrow_forwardC++ Given code #include <iostream>using namespace std; class Node {public:int data;Node *pNext;}; void displayNumberValues( Node *pHead){while( pHead != NULL) {cout << pHead->data << " ";pHead = pHead->pNext;}cout << endl;} //Option 1: Search the list// TODO: complete the function below to search for a given value in linked lsit// return true if value exists in the list, return false otherwise. ?? linkedlistSearch( ???){ } //Option 2: get sum of all values// TODO: complete the function below to return the sum of all elements in the linked list. ??? getSumOfAllNumbers( ???){ } int main(){int userInput;Node *pHead = NULL;Node *pTemp;cout<<"Enter list numbers separated by space, followed by -1: "; cin >> userInput;// Keep looping until end of input flag of -1 is givenwhile( userInput != -1) {// Store this number on the listpTemp = new Node;pTemp->data = userInput;pTemp->pNext = pHead;pHead = pTemp;cin >> userInput;}cout <<"…arrow_forward
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