Chemistry
10th Edition
ISBN: 9781305957404
Author: Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher: Cengage Learning
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- Part 2 The Haber process produces ammonia (NH3) for the chemical industry from nitrogen (N₂) and hydrogen (H₂) as shown in the chemical equation below. This is a reversible reaction. N2 (8) + 3H2(g) → 2NH3 (8) AH = -92 kJ mol-¹ (exothermic) The following questions relate to the effect of changing factors that influence the direction of the above reaction, according to Le Chatelier's principle. For each change in factor (i - iv) listed in the Table, you need to: state the direction of equilibrium, give a reason for your choice, identify if the amount of ammonia produced will increase or decrease. Factor Decrease in concentration of N₂ i) ii) Increase in pressure iii) Increase in temperature iv) A catalyst is added Direction (shift) of equilibrium Scientific explanation for stated direction of equilibrium. Amount of NH3 Increases / decreases Part 3 During this reaction, compromises are made to speed up and maximise the production of ammonia. i) ii) Suggest why a moderate amount of…arrow_forward2 ·als NaOH, H ethanol heatarrow_forwardTry Again Row 3: Your answer is wrong. In addition to checking your math, check that you used the right data and DID NOT round any intermediate calculations. A student runs two experiments with a constant-volume "bomb" calorimeter containing 1100. g of water (see sketch at right). First, a 7.000 g tablet of benzoic acid (CH₂CO₂H) is put into the "bomb" and burned completely in an excess of oxygen. (Benzoic acid is known to have a heat of combustion of 26.454 kJ/g.) The temperature of the water is observed to rise from 15.00 °C to 53.26 °C over a time of 12.3 minutes. Next, 5.420 g of acetylene (C₂H₂) are put into the "bomb" and similarly completely burned in an excess of oxygen. This time the temperature of the water rises from 15.00 °C to 74.42 °C. Use this information, and any other information you need from the ALEKS Data resource, to answer the questions below about this reaction: Is this reaction exothermic, endothermic, or neither? If you said the reaction was exothermic or…arrow_forward
- Could someone please help! No plagiarism Please! 3. Draw an or find an image of an endothermic reaction or an exothermic reaction. Explain what makes it the type of reaction you chose to illustrate. Include arrows to show what direction the overall enthalpy of reaction (energy of reaction) flows. 4. Ammonium nitrate dissolves in water via the following reaction: NH4NO3(s) → NH4+(aq) + NO3-(aq) The bond energies of the compounds in the reaction are as follows: NH4NO3 = 3040 kJ/mol NH4+ = 1564 kJ/mol NO3- = 1009 kJ/mol How much total energy does the reaction have, and how will the environment change when the reaction occurs? Please show all of your workarrow_forward113 kJ of heat is absorbed when one mole of carbon reacts with one mole of water. Energy + C + H2O → CO + H2 According to the reaction above it can be concluded that the reaction is a endothermic, because the change of enthalpy was negative b exothermic, because the change of enthalpy was negative c exothermic, because the change of enthalpy was positive d endothermic, because the change of enthalpy was positivearrow_forwardUse the following information to answer Questions 6-9: A sample of NH4NO3 with a mass of 5.0 g is dissolved in 40.1 g of deoinized water in a calorimeter. The initial temperature of the water is 21.2 oC. The final temperature of the solution is 15.4 oC. The calorimeter constant = 25.2 J/oC. Is the following statement true or false? This process is exothermic. True Falsearrow_forward
- 4. When 1.00 L of 1.05 M Ba(NO3)2 solution is mixed with 1.00 L of 1.10 M NazSO4 solution at 25.0°C in a coffee-cup calorimeter. The reaction is Ba(NOs)2(aq) + NazSO4(aq) → BaSO4(s) + 2NANO:(aq). The final temperature of the mixture increases to 28.1°C. Calculate the enthalpy change per mole for this process. (Assuming C=4.18 J °C' g' and density of the final solution is 1.05 g/ml).arrow_forwardThe sugar arabinose, C5 H10 O5, is burned completely in oxygen in a calorimeter. C5 H10 O5 (8) + 502(g) → 5CO2(g) + 5H2 O(1) Burning a 0.541 g sample caused the temperature to rise from 20.00°C to 20.54°C. The heat capacity of the calorimeter and its contents is 15.2 kJ/°C. Calculate AH for the combustion reaction per mole of arabinose. ΔΗ+ kJ/molarrow_forward33 a b C d e Consider the hypothetical thermochemical equation 3A+B→2C for which AH = 61.5 kJ/mol. L L L L L If you have 5.30 moles of A, what quantity of heat, in kJ, would be absorbed? If the reaction absorbs 345 kJ of heat, What quantity in moles of C would be produced? What would AH, in kJ/mol, be for the reaction 2 C → 3 A + B? What would AH, in kJ/mol, be for the reaction 9A + 3 B →6 C? Which one of the following reactions would have an enthalpy change of -2xAH? Here, AH refers to the enthalpy change of the original reaction.arrow_forward
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