How long (in seconds) does it take for the concentration of A to decrease to 0.00800 M? Enter your answer with one decimal place and no units. 1/[A] 120 100 80 60 40 20 0 0 10 20 y = 0.7957x + 61.714 R² = 0.9998 30 Time (sec) 40 50 60
How long (in seconds) does it take for the concentration of A to decrease to 0.00800 M? Enter your answer with one decimal place and no units. 1/[A] 120 100 80 60 40 20 0 0 10 20 y = 0.7957x + 61.714 R² = 0.9998 30 Time (sec) 40 50 60
Introductory Chemistry: A Foundation
9th Edition
ISBN:9781337399425
Author:Steven S. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Donald J. DeCoste
Chapter15: Solutions
Section: Chapter Questions
Problem 134AP
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Question
![How long (in seconds) does it take for the concentration of A to decrease
to 0.00800 M? Enter your answer with one decimal place and no units.
1/[A]
120
100
80
60
40
20
0
0
10
20
y = 0.7957x + 61.714
R² = 0.9998
30
Time (sec)
40
50
60](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fc6ff1f88-0380-4e44-8445-f5330d9849e2%2F9a7b9fab-6ec4-4a57-b2ce-6c505dc68a88%2F743eqc_processed.png&w=3840&q=75)
Transcribed Image Text:How long (in seconds) does it take for the concentration of A to decrease
to 0.00800 M? Enter your answer with one decimal place and no units.
1/[A]
120
100
80
60
40
20
0
0
10
20
y = 0.7957x + 61.714
R² = 0.9998
30
Time (sec)
40
50
60
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