Hemophilia is an X linked recessive condition. A woman has a brother who is hemophiliac and while she does not have the condition she has a brother who has the condition. Hemophilia is due to a mutation in a clotting factor. The exon intron structure of a clotting factor gene is shown below. Exons are blue rectangles. You analyze the DNA of the woman and her brother by PCR using primers which bind to the left and right of exon 4. The results of the gel of the PCR products are shown below. The negative end of the gel is at the top, the positive is at the bottom. Based on these results O O O O Exon 1 23 Woman The woman is likely to be homozygous for the disease allele The woman is likely to be homozygous for the non-disease allele The woman can not be genetically related to her "brother" The woman is likely to be heterozygous 5 Brother 6 7 H 8

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Hemophilia is an X linked recessive condition. A woman has a
brother who is hemophiliac and while she does not have the
condition she has a brother who has the condition. Hemophilia is
due to a mutation in a clotting factor. The exon intron structure
of a clotting factor gene is shown below. Exons are blue
rectangles.
You analyze the DNA of the woman and her brother by PCR
using primers which bind to the left and right of exon 4. The
results of the gel of the PCR products are shown below. The
negative end of the gel is at the top, the positive is at the
bottom. Based on these results
Exon 1
2 3
Woman
● The woman is likely to be homozygous for the disease allele
The woman is likely to be homozygous for the non-disease allele
The woman can not be genetically related to her "brother"
The woman is likely to be heterozygous
5
Brother
6
7 8
Transcribed Image Text:Hemophilia is an X linked recessive condition. A woman has a brother who is hemophiliac and while she does not have the condition she has a brother who has the condition. Hemophilia is due to a mutation in a clotting factor. The exon intron structure of a clotting factor gene is shown below. Exons are blue rectangles. You analyze the DNA of the woman and her brother by PCR using primers which bind to the left and right of exon 4. The results of the gel of the PCR products are shown below. The negative end of the gel is at the top, the positive is at the bottom. Based on these results Exon 1 2 3 Woman ● The woman is likely to be homozygous for the disease allele The woman is likely to be homozygous for the non-disease allele The woman can not be genetically related to her "brother" The woman is likely to be heterozygous 5 Brother 6 7 8
You are interested in identifying genes that determine tail length
in dachsunds. You analyze the genome of several dachsunds and
look for SNPS that correlate with tail length. The results are
shown here
***
pog
O O O O
Spot
Rover
Chase
Frisbee
Cindee
Checkers
SNP 1
SNP 2
SNP 3
Tail Length
(cm)
10
12
SNP 4
9
4
3
10
SNP 1
C
C
C
G
C
C
SNP 2
A
T
T
A
A
T
SNP 3
C
C
C
G
G
с
Based on these results which SNP is best correlated with tail
length
SNP 4
G
G
T
T
T
G
Transcribed Image Text:You are interested in identifying genes that determine tail length in dachsunds. You analyze the genome of several dachsunds and look for SNPS that correlate with tail length. The results are shown here *** pog O O O O Spot Rover Chase Frisbee Cindee Checkers SNP 1 SNP 2 SNP 3 Tail Length (cm) 10 12 SNP 4 9 4 3 10 SNP 1 C C C G C C SNP 2 A T T A A T SNP 3 C C C G G с Based on these results which SNP is best correlated with tail length SNP 4 G G T T T G
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