Giventhe following assignment of some program’s virtual pages to physical pages in a system with 4 KiB byte pages, what physical memory address corresponds to virtual address 20000? (All values are given in decimal.)

Draw a picture illustrating the contents of memory, given the following data declarations: (You need to draw a diagram showing the memory addresses and their contents.) Assume that your data segment starts at 0x1000 in memory. Your answer should fill the table below and explain why. Addres Hexadecimal Hexadecimal S Value Value 0x1000 Ox |0x Ox Ox 0x Name: asciiz "Jones" Age: byte 48 Numbers: word 11, 20 Letter1: asciiz "Car" Letter2: .byte 25 Hexadecimal Value Hexadecimal Value

The program below uses pointer arithmetic to determine the size of a 'char'variable. By using pointer arithmetic we can find out the value of 'cp' and thevalue of 'cp+1'. Since cp is a pointer, this addition involves pointer arithmetic:adding one to a pointer makes the pointer point to the next element of the sametype.For a pointer to a char, adding 1 really just means adding 1 to the address, butthis is only because each char is 1 byte.1. Compile and run the program and see what it does.2. Write some code that does pointer arithmetic with a pointer to an int anddetermine how big an int is.3. Same idea – figure out how big a double is, by using pointer arithmetic andprinting out the value of the pointer before and after adding 1.4. What should happen if you added 2 to the pointers from exercises 1through 3, instead of 1? Use your program to verify your answer.#include <stdio.h>int main( ){ char c = 'Z'; char *cp = &c; printf("cp is %p\n", cp); printf("The character at cp is…

1. Suppose an array with six rows and eight columns is stored in a row major order starting at address 20 (base 10). If each entry in the array requires only one memory cell, what is the address on the entry in the third row and fourth columns? What if each entry requires two memory cells?

Q.2 Suppose a system has a logical address space of size 25 (m=5), a page size of 4 bytes, and a physical memory of 128 bytes. Given the following page table, find out the respective physical addresses for each of the logical address listed in Table 2. (Note: all addresses are expressed in decimal number system) Table 1: Page table 0 2 5 7 0 15 1 2 3 4 5 18 6 20 7 22 Table 2: Fill out this table with corresponding physical memory addresses Logical Address Physical Address 0 6 10 17 23

Complete the following sequence of three MIPS instructions: mul28: $t0, 28 mul $to ir by dragging four items from the below list into the correct spaces. Your code should implement a procedure, using the standard conventions covered in class for passing parameters and returning results, that returns the product of its argument and 28. $ra li sb $a0 $v0 Ib move lui Give a sequence of two MIPS instructions that branches to the target address represented by the name "loop" if and only if the contents of $$0 are less than or equal to the contents of $s1. Do this by dragging two items from the below list into the correct spaces. slt $at, $s1, $s0 bne $at, $zero, loop bltz $at, loop slt $at, $s0, $s1 beq $at, $zero, loop

Question 9

E In the following code block(Reference:Q11), you will a set of assembly instructions with corresponding line numbers (line numbers are for informational purpose only and they are not part of the source code). 33 34 35 36 37 38 39 40 41 42 43 44 45 46 47 mov edx, 5 dec ecx jmp LABEL1 mov eax, 1 LABEL1: mul edx jmp ecx mov edx, 0678h sub edx, eax jmp DWORD PTR [edx] neg ebx add ecx, ebx mov eax, 0 For each of the conditions/scenario listed below, indicate the corresponding line number (that cause or is associated with the condition/scenario). Enter 0 (Zero) if the condition is not caused by the block of code. 1) Memory indirect jump: type your answer... type your answer... type your answer... type your answer... 2) Register indirect jump: 3) Relative short jump: type your answer... 5) Two's complement type your answer... 4) Relative near jump: 6) Unreachable code

list: .word 3, 0, 1, 2, 6, -2, 4, 7, 3, 7 size: .word 10 Develop a mips code with a Mars simulator that reads this sequence and counts those <0 (negative) and >=0 (zero or positive) and prints what it finds to the screen.