AutoSave On Capacity H5 - Last Modified: 6m ago - Lindsey Littlefield File Home Insert Draw Design Layout References Mailings Review View Help O Search A Share P Comments O Find - S Replace X Cut - A^ A Aa- A AаBЬСcDd AaBbСcDd AaBbC AаBЬСс[ Аа B АавьссD Helvetica 12 AaBbCcDd AaBbCcDd AaBbCcDd B Copy Paste E- 1 Normal 1 No Spac. Heading 1 Heading 2 Subtitle Intense E... Dictate BIU - ab x, x A - l-A- Title Subtle Em... Emphasis A Select - S Format Painter Clipboard Font Paragraph Styles Editing Voice .. . . . . 1. . . |: . . 2.. . | · .. ITE 221 Capacity 04/15/2020 Lindsey Littlefield A system currently accessing 3.8 G bytes of RAM and 10 M bytes of ROM. Compute the number of address lines required to access the designated storage. 2. For a given # of lines how many more storage space is accessible? Currently out of 3.8 G, 3 G is used by the system programs, .4 G by an application. Can we expand the memory by another 890 M to support a new application? show total storage use and available. Show all your work. 3. RAM = 3.8 G ROM = 10 M Total Capacity = (3.8 G + 10 M) = 3.81 G The number of address lines = 32 lines 32 lines allows for 4 G 3.8G – (3G +.4G) = 3.4G 4G – 3.4G = 0.6G left .89 * 1024 = 911.36 M so yes it does support Page 1 of 1 143 words + 85% 7:44 PM O Type here to search 4/15/2020 O Zoom Participants (14) Q Find a participant (5 LL Lindsey Littlefield (Me) ite221lecture - Word File Home Insert Design Layout References Mailings Review View O Tell me what you want to do.. Anwari, M H. 2 Share AH Anwari, Hashem (Host) X Cut P Find - Calibri 11 - A A Aa - АавьСсDc AаBьссDс AaBbC AаBbCc[ Aав давьссС АавЬСсD AaвьссD 暗Copy abc Replace Paste U - abe X, x’ A - aly , A- 1 Normal I No Spac. Heading 1 Heading 2 Subtitle Subtle Em. Emphasis ws Waqas Siddiqui Title Format Painter A Select- Clipboard Font Paragraph Styles Editing A aziz o Example >> ... Raise Hand yes go slower go faster no more A system currently accessing 3.1 G bytes of RAM and 0.3 Gbytes of ROM. Compute the number of address lines required to access the designated storage. For a given # of lines how many more storage space is accessible can we expand the memory by another 600Mbytes to support a program to run Unmute Me Zoom Group Chat From Patrick Nero to Everyone: RAM =3.1 G 3.1G+ 0.3G 3.4 G 3.1 G + 0.3 G ROM=0.3 G total capacity= 3.4 G From Erick Bonilla to Me: (Privately) л The number of address lines= ? 32 lines 32 lines allows 4 G From Erick Bonilla to Everyone: 4G- 3.4G =.6G .6* 1024 =614 M yes it does support From Kasra Kamgar to Everyone: got it thanks Patrick From Patrick Nero to Everyone: np man Page 59 of 70 2076 words 188% To: Erick Bonilla v (Privately) Type message here... 9:23 PM O Type here to search PDF 4/13/2020
AutoSave On Capacity H5 - Last Modified: 6m ago - Lindsey Littlefield File Home Insert Draw Design Layout References Mailings Review View Help O Search A Share P Comments O Find - S Replace X Cut - A^ A Aa- A AаBЬСcDd AaBbСcDd AaBbC AаBЬСс[ Аа B АавьссD Helvetica 12 AaBbCcDd AaBbCcDd AaBbCcDd B Copy Paste E- 1 Normal 1 No Spac. Heading 1 Heading 2 Subtitle Intense E... Dictate BIU - ab x, x A - l-A- Title Subtle Em... Emphasis A Select - S Format Painter Clipboard Font Paragraph Styles Editing Voice .. . . . . 1. . . |: . . 2.. . | · .. ITE 221 Capacity 04/15/2020 Lindsey Littlefield A system currently accessing 3.8 G bytes of RAM and 10 M bytes of ROM. Compute the number of address lines required to access the designated storage. 2. For a given # of lines how many more storage space is accessible? Currently out of 3.8 G, 3 G is used by the system programs, .4 G by an application. Can we expand the memory by another 890 M to support a new application? show total storage use and available. Show all your work. 3. RAM = 3.8 G ROM = 10 M Total Capacity = (3.8 G + 10 M) = 3.81 G The number of address lines = 32 lines 32 lines allows for 4 G 3.8G – (3G +.4G) = 3.4G 4G – 3.4G = 0.6G left .89 * 1024 = 911.36 M so yes it does support Page 1 of 1 143 words + 85% 7:44 PM O Type here to search 4/15/2020 O Zoom Participants (14) Q Find a participant (5 LL Lindsey Littlefield (Me) ite221lecture - Word File Home Insert Design Layout References Mailings Review View O Tell me what you want to do.. Anwari, M H. 2 Share AH Anwari, Hashem (Host) X Cut P Find - Calibri 11 - A A Aa - АавьСсDc AаBьссDс AaBbC AаBbCc[ Aав давьссС АавЬСсD AaвьссD 暗Copy abc Replace Paste U - abe X, x’ A - aly , A- 1 Normal I No Spac. Heading 1 Heading 2 Subtitle Subtle Em. Emphasis ws Waqas Siddiqui Title Format Painter A Select- Clipboard Font Paragraph Styles Editing A aziz o Example >> ... Raise Hand yes go slower go faster no more A system currently accessing 3.1 G bytes of RAM and 0.3 Gbytes of ROM. Compute the number of address lines required to access the designated storage. For a given # of lines how many more storage space is accessible can we expand the memory by another 600Mbytes to support a program to run Unmute Me Zoom Group Chat From Patrick Nero to Everyone: RAM =3.1 G 3.1G+ 0.3G 3.4 G 3.1 G + 0.3 G ROM=0.3 G total capacity= 3.4 G From Erick Bonilla to Me: (Privately) л The number of address lines= ? 32 lines 32 lines allows 4 G From Erick Bonilla to Everyone: 4G- 3.4G =.6G .6* 1024 =614 M yes it does support From Kasra Kamgar to Everyone: got it thanks Patrick From Patrick Nero to Everyone: np man Page 59 of 70 2076 words 188% To: Erick Bonilla v (Privately) Type message here... 9:23 PM O Type here to search PDF 4/13/2020
Computer Networking: A Top-Down Approach (7th Edition)
7th Edition
ISBN:9780133594140
Author:James Kurose, Keith Ross
Publisher:James Kurose, Keith Ross
Chapter1: Computer Networks And The Internet
Section: Chapter Questions
Problem R1RQ: What is the difference between a host and an end system? List several different types of end...
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Hello I need help with the following question, I have provided my work that I have done and an example of completed work from the class.
This is the question I need help with.
A system currently accessing 3.8 G bytes of RAM and 10 M bytes of ROM. Compute the number of address lines required to access the designated storage.
For a given # of lines how many more storage space is accessible?
Currently out of 3.8 G, 3 G is used by the system programs, .4 G by an application.
Can we expand the memory by another 890 M to support a new application? show total storage use and available. Show all your work.
Transcribed Image Text:AutoSave On
Capacity H5 - Last Modified: 6m ago -
Lindsey Littlefield
File
Home
Insert
Draw
Design
Layout
References
Mailings
Review
View
Help
O Search
A Share
P Comments
O Find -
S Replace
X Cut
- A^ A Aa- A
AаBЬСcDd AaBbСcDd AaBbC AаBЬСс[ Аа B АавьссD
Helvetica
12
AaBbCcDd AaBbCcDd AaBbCcDd
B Copy
Paste
E-
1 Normal
1 No Spac. Heading 1
Heading 2
Subtitle
Intense E...
Dictate
BIU - ab x, x A - l-A-
Title
Subtle Em...
Emphasis
A Select -
S Format Painter
Clipboard
Font
Paragraph
Styles
Editing
Voice
.. . . . . 1. . . |: . . 2.. . | · ..
ITE 221
Capacity
04/15/2020
Lindsey Littlefield
A system currently accessing 3.8 G bytes of RAM and 10 M bytes of ROM. Compute
the number of address lines required to access the designated storage.
2.
For a given # of lines how many more storage space is accessible?
Currently out of 3.8 G, 3 G is used by the system programs, .4 G by an application.
Can we expand the memory by another 890 M to support a new application? show total
storage use and available. Show all your work.
3.
RAM = 3.8 G
ROM = 10 M
Total Capacity = (3.8 G + 10 M) = 3.81 G
The number of address lines = 32 lines
32 lines allows for 4 G
3.8G – (3G +.4G) = 3.4G
4G – 3.4G = 0.6G left
.89 * 1024 = 911.36 M so yes it does support
Page 1 of 1
143 words
+ 85%
7:44 PM
O Type here to search
4/15/2020
Transcribed Image Text:O Zoom
Participants (14)
Q Find a participant
(5
LL
Lindsey Littlefield (Me)
ite221lecture - Word
File
Home
Insert
Design
Layout
References
Mailings
Review
View
O Tell me what you want to do..
Anwari, M H. 2 Share
AH Anwari, Hashem (Host)
X Cut
P Find -
Calibri
11 - A A Aa -
АавьСсDc AаBьссDс AaBbC AаBbCc[ Aав давьссС АавЬСсD AaвьссD
暗Copy
abc Replace
Paste
U - abe X, x’ A - aly , A-
1 Normal
I No Spac. Heading 1
Heading 2
Subtitle
Subtle Em. Emphasis
ws Waqas Siddiqui
Title
Format Painter
A Select-
Clipboard
Font
Paragraph
Styles
Editing
A
aziz
o Example
>>
...
Raise Hand
yes
go slower
go faster
no
more
A system currently accessing 3.1 G bytes of RAM and 0.3 Gbytes of ROM.
Compute the number of address lines required to access the designated
storage. For a given # of lines how many more storage space is accessible can
we expand the memory by another 600Mbytes to support a program to run
Unmute Me
Zoom Group Chat
From Patrick Nero to Everyone:
RAM =3.1 G 3.1G+ 0.3G 3.4 G
3.1 G + 0.3 G
ROM=0.3 G total capacity= 3.4 G
From Erick Bonilla to Me: (Privately)
л
The number of address lines= ? 32 lines
32 lines allows 4 G
From Erick Bonilla to Everyone:
4G- 3.4G =.6G
.6* 1024 =614 M yes it does support
From Kasra Kamgar to Everyone:
got it thanks Patrick
From Patrick Nero to Everyone:
np man
Page 59 of 70
2076 words
188%
To:
Erick Bonilla v (Privately)
Type message here...
9:23 PM
O Type here to search
PDF
4/13/2020
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