Write a simple encryption/decryption program. Function encrypt takes a character pointer as a parameter and uses pointer-subscript notation to change the value in the address pointed to by adding 1 to it. Function decrypt takes a character pointer as a parameter and uses pointer notation to change the value in the address pointed to by

plz help with c++....and keep output same as given and paste indented code plzz

help with c++...paste indented code plzz

Write a C function that is given a pointer to memory, the number of bytes of memory the pointer points at, and two pointers to uint32_t. Your job is to treat the pointer as if it were a pointer to an array of uint32_t, find the min and max values of the array, and write the results to the locations pointed at by the uint32_t pointers. The number of bytes will be a positive multiple of 4. Do not worry about endianess in this problem. Note the tester has command line options -Wall -Wextra -Werror -fsanitize=address to help you catch errors.

Write a c++ function that accepts an array of doubles and the array’s size as its only arguments. The function should use dynamic memory allocation to create a new array that is double the size of the argument array. The function should copy the contents of the argument array to the second half of the new array and initialize the first half of the new 0s. The function should return a pointer to the new array. So, if the original array contained 1 2 3 4, the new array should contain 0 0 0 0 1 2 3 4. So, if the original array contained 1 2 3 4, the new array should contain 0 0 0 0 1 2 3 4.

Define a problem with user input, user output, Pointer, with const and sizeof operator. If no output explain the reason why and what you are going to do make sure it does not happen again aka learning from your mistakes.   Problem: Design: Code: Output:

Build a C program that performs the following operations: Declares three pointer variables called iPtr of type int, cPtr of type char, and fFloat of type float Declares three new variables called iNumber of int type, fNumber of float type, and cCharacter of char type Assigns the address of each non-pointer variable to the matching pointer variable Prints the value of each non-pointer variable Prints the value of each pointer variable Printer the address of each non-pointer variable Prints the address of each pointer variable

The program below uses pointer arithmetic to determine the size of a 'char'variable. By using pointer arithmetic we can find out the value of 'cp' and thevalue of 'cp+1'. Since cp is a pointer, this addition involves pointer arithmetic:adding one to a pointer makes the pointer point to the next element of the sametype.For a pointer to a char, adding 1 really just means adding 1 to the address, butthis is only because each char is 1 byte.1. Compile and run the program and see what it does.2. Write some code that does pointer arithmetic with a pointer to an int anddetermine how big an int is.3. Same idea – figure out how big a double is, by using pointer arithmetic andprinting out the value of the pointer before and after adding 1.4. What should happen if you added 2 to the pointers from exercises 1through 3, instead of 1? Use your program to verify your answer.#include <stdio.h>int main( ){ char c = 'Z'; char *cp = &c; printf("cp is %p\n", cp); printf("The character at cp is…

Using C++ Language Write a function call with arguments tensPlace, onesPlace, and userInt. Be sure to pass the first two arguments as pointers. Sample output for the given program: tensPlace = 4, onesPlace = 1  Code:  #include <stdio.h> void SplitIntoTensOnes(int* tensDigit, int* onesDigit, int DecVal){   *tensDigit = (DecVal / 10) % 10;   *onesDigit = DecVal % 10;} int main(void) {   int tensPlace;   int onesPlace;   int userInt;    scanf("%d", &userInt);    /* Your solution goes here  */    printf("tensPlace = %d, onesPlace = %d\n", tensPlace, onesPlace);    return 0;}