Given the system above, F1 = 34 N, F2 = 96 N, M = 245 N-m, a = 3 m, b = 2 m, and a = 40°. (a) Represent the system using a single force. Determine the magnitude of the force and its location relative to point A. Round all answers to the nearest integer. The magnitude of the force (N) is: N The position of the force relative to A (m) is: m (b) Represent the system using a force and a couple moment acting at point C. Determine the magnitudes of the force and the couple moment. Round all answers to the nearest integer. The magnitude of the force (N) is: N The magnitude of the couple moment ((N-m) is: N-m

Calculate both resultant force and resultant moment. This is one question.

1.1.4 - Show all work please.

The two blocks used in a measuring device have negligible weight. The spring is compressed 4 in. when in the position shown. The end of the screw is smooth and the coefficient of static friction at all other points of contact is μ = 0.35. (Figure 1) Figure P k = 20 lb/in. B 45° A 60° 1 of 1 Part A Determine the smallest axial force P which the adjustment screw must exert on B in order to start the movement of B downward. Express your answer to three significant figures and include the appropriate units. P = Submit μA Value Provide Feedback Request Answer Units

The coefficient of static friction between the drum and brake bar is μs = 0.4. If the moment M = 35 N ⋅ m, determine the smallest force P that needs to be applied to the brake bar in order to prevent the drum from rotating.Also determine the corresponding horizontal and vertical components of reaction at pin O. Neglect the weight and thickness of the brake bar. The drum has a mass of 25 kg.

3. Please show your complete solution.

Three forces are applied to the beam. F₂ = (-250 i + 6503 + -300 ) N. Variable F₁ F3 d₁ d₂ d3 Value Z 300 N 350 N 2 m 2.5 m 0.5 m F2 d3. d2 d1 F₁ Values for the figure are given in the following table. Note the figure may not be to scale. F3 Y → a. Replace the force system with an equivalent force, FR, express as a cartesian vector. b. Replace the force system with an equivalent couple → moment acting at point 0, (MR)o, express as a cartesian vector. Round your final answers to 3 significant digits/figures.

1. Use the Macaulay/singularity functions to obtain a formula for the bending moment M. 2. Use this to get a formula for Elv as a function of x, including two constants of integration Cp and C2 3. Determine the values of C and C and write out Elvin terms of P, L and a. 4. If a = L/3 what is the maximum value of -Eiv/Pa?? Write it as a positive number in the box, to two decimal places. (PLEASE ANSWER ASAP AND CORRECTLY! THANK YOU)

Please correct my understanding of this question. -In the equation of the moment at point A, there is a value, 36(11.5). I assume that is a force from the distributed load. -If you are finding the moment at point A, wouldn't you only need one value from the distributed load which is 27(10)? So my question is how do you get the value of 36 and 11.5, separately. And what is it for?

Solve the problem by the moment-area method. The beam has constant flexural rigidity EI. A simple beam AB supports two concentrated loads P at the positions shown in the figure. B C 4. 4 A support C at the midpoint of the beam is positioned at distance d below the beam before the loads are applied. Assuming that d = 12 mm, L = 5.4 m, E = 200 GPa, and I = 193 x 10° mm, calculate the magnitude of the loads P (in kN) so that the beam just touches the support at C. 163.87 x kN