Biochemistry
9th Edition
ISBN: 9781319114671
Author: Lubert Stryer, Jeremy M. Berg, John L. Tymoczko, Gregory J. Gatto Jr.
Publisher: W. H. Freeman
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- Which of the structures above is a component of sucrose and predominantly forms a furanose ring structure? A. H C I H-C-OH НО-С-Н I Н-С-ОН I H-C-OH I CH2OH A В D B. H =O но-с-н I но-с-н I н-с-он Н-С-ОН I CH₂OH CH2OH I c=0 I но-с-н I H— C -ОН H— C-OH CH₂OH D. COOH H-C-OH НО-С-Н I но-с-н I н-с-он CH₂OHarrow_forward18arrow_forwardThe sugar molecules shown below are a) Enantiomers b) Epimers c) Anomers d) Diastereomersarrow_forward
- Classify the monosaccharides. H H-C- -OH H-C- -OH H- CH₂OH D-erythrose H- CH₂OH FO -OH H. CH₂OH D-erythrulose H- -OH -OH H-C OH CH₂OH H- D-ribose CH₂OH OH H-C OH CH₂OH D-ribulose H H-C- CH₂OH D-glyceraldehyde -OH HO- -C- H- CH₂OH FO -H -C- -OH H-C OH CH₂OH D-fructose CH₂OH C=O CH₂OH Dihydroxyacetone triose Answer Bank ketose hexose aldose tetrose pentosearrow_forwardExplain the structure and its componentsarrow_forwardWhat are the structural differences between bilirubin and urobilin? (Select all that apply.) O Ring is opened in the first compound, but is not in the second compound. Several methylene bridges are reduced in the second compound. O Iron atom is absent in the second compound, but is present in the first compound. The central methylene bridge is reduced in the second compound, but is not in the first compound. O Ring is opened in the second compound, but is not in the first compound. Some vinyl groups are reduced into ethyl groups in the second compound. The central methylene bridge is oxidised in the second compound, but is not in the first compound. O Some vinyl groups are reduced into ethyl groups in the first compound.arrow_forward
- Name the types of glycosidic bonds found in this olygomer, from left to right (from 1 to 3) CH 20H CH 2OH CH 2OH но OH OH OH OH OH OH O alpha1-1, alpha1-4, n O alpha1-4, alpha1-4, n O alpha1-4, beta1-2 O alpha1-4, beta1-4 O beta1-4, alpha 1-4 « Previous Next Not saved Submit Quizarrow_forwardAldose monosaccharides can be oxidized when treated with a mild oxidizing agent. In this reaction, the aldehyde group of the open-chain aldose is oxidized to a carboxylic acid group. In basic solution, ketose monosaccharides can also be oxidized, forming carboxylic acids because they can undergo a rearrangement to an aldose form. Monosaccharides (cyclic hemiacetals) can also react with an alcohol to form acetals, called glycosides, and water. In this reaction, the OH of the anomeric carbon is replaced by the OR group of the alcohol. D-ribose (Figure 1) is treated with a mild oxidizing agent. Edit the structure for D-ribose to show the product of this reaction. M Edit the molecule on the canvas by choosing buttons from the Tools (for bonds), Atoms, and Advanced Template toolbars. The single bond is active by default. Include all hydrogen atoms. ► View Available Hint(s) [1] A H 12D H H H H 7 L EXP. CONT.i L 1 -O-H O H ew -O-H enodic Table -O-H H C N O S CI Br I P Farrow_forwardPlease label this structure.arrow_forward
- The following hexoses are....arrow_forwardHow much nystatin stock (50 mg/mL) needs to be added to 15 mL of tryptic soy agar to give a final concentration of 50 μg/mL?arrow_forwardWhich of the following represents a pair of epimers? A с OH OH -OH OH НО-С-Н НО-С-Н OH O C-H OH O C-H H-C-OH НО-С-Н H-C-OH H-C-OH H-C-OH НО-С-Н H-C-OH НО-С-н CH.OH CH.OH В н 0 Н- C-OH H-C-OH H-C-OH H-C-OH CH, OH D Н 20 НО -H но- -Н FO H+H H-C=O но-с-н H-C-OH CH,OH Н-С=0 но он H-C=0 HO-OH O= н-н H-C=Oarrow_forward
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