Given a virtual memory of size 4 GiB, physical memory of size 1 GiB, and page size equal to 256 KiB.  How many bits are used to specify a virtual page number?

Q: In a main memory-disk virtual storage system, the page size is 1KByte and the FIFO algorithm is used…

A: After each memory reference, the contents of three page frames must be filled up in a table so that…

Q: Given the following expression, Z = [(G+E) * A] – [H * (A + S / L)] Write the following machine…

A: Z=[(G+E)*A]-[H*(A+S/L)] Zero-address instruction: It represents the postfix notation of the…

Q: Show how the value Oxabcdef12 would be arranged in memory of a little-endian machine. Place commas…

A: 1) Endianness is the order or sequence of bytes of a word of digital data in computer memory. We…

Q: I have a 128-bit computer where addresses are 128 bits wide. I want to implement virtual memory with…

A: The following solution is

Q: Consider a logical address with a page size of 16 KB. How many bits must be used to represent the…

A: The number of bits required to store the page offset in the logical address is 14. Therefore, the…

Q: Consider a logical address space of 32 pages of 1024 words each, mapped onto a physical memory of 8…

A: Logical Address space: This address space is generated by the process running on the CPU for a…

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Q: A computer system has 6 page frames. The table below shows the time of loading, the time of last…

A: Understanding Page ReplacementPurpose: When a program needs a page that's not currently in the main…

Q: QUESTION 15 Given the logical address OxD953 (in hexadecimal), What is the page number and the page…

A: The given logical address is 0xD953  (in hexadecimal)                                           =…

Q: Consider a disk pack with 32 surfaces, 64 tracks and 512 sectors per pack. 256 bytes of data are…

A: The answer is

Q: Determine the number of page table entries (PTEs) that areneeded for the following combinations of…

A: Number of page table entries = address size / page size

Q: Consider a logical address space of eight pages of 1024 words ach, mapped on to a physical memory of…

A: ANSWER:-

Q: If logical address is (0001100001011) binary find page number p: displacement

A: Logical address: 0001100001011 Page number: 00011000 Displacement: 01011 Suppose the page addressed…

Q: 32 bit physi dress and us ase register 1. Each page I. e. Each entr

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Q: In a main memory-disk virtual storage system, the page size is 1KByte and the OPTIMAL algorithm is…

A: We need to fill in the contents of the three page frames after each memory reference in a table and…

Q: A machine has 48-bit virtual addresses and 32-bit physical addresses. Pages are 8 KB. How  many…

A: Actually, given information: A machine has 48-bit virtual addresses  32-bit physical addresses.

Q: We have a byte-addressable computer with fully associative mapping, 16-bit main memory addresses,…

A: Associative Mapping:  The associated memory stores and targets both memory terms in associative…

Q: Assume we have 1 GB of physical memory. Inverted page table is used. Page size is 16 KB. Each entry…

A: In the inverted page table, indexing is done with respect to the frame number instead of the logical…

Q: Consider a system with pages of size 512. If an address in binary is: 0011 1001 0111 0111 The…

A: Introduction: In computer systems that use paging, memory addresses are divided into two parts: the…

Q: ry split into pages. If each byte in the virtual memory has a virtual address, and the last 8 bits…

A: Pages are typically 512 to 8192 bytes in size, with 4096 being the most common value. For reasons…

Q: If logical addresses are represented using m bits as shown below, where m=4 and n=2. What is the…

A: Actually, memory is used to stores the data.

Q: Consider a system with N bytes of physical RAM, and M bytes of virtual address and frames are K…

A: Here the virtual memory size = M bytes And page size is K bytes.  The virtual address is divided…

Q: Consider a logical address space of 1024 pages with 2 KB page size, mapped onto a physical memory of…

A: The above question can be solved using formula:                                    Size of physical…

Q: Consider a 64-bit system with virtual memory. If the size of page is 32KB and the size of page table…

A: Virtual memory size = 2^64B Page size = 32KB = 2^15B Page table entry size = 16B = 2^4 B

Q: The memory location at address of 0X003FB01 contains 1-byte memory variable J (0010_0001), and the…

A: The correct option is (c) Answer 1 and Answer 2 are given below choose one from them which is easy…

Q: Assume a 32-bit virtual address and 4 MBs of memory (i.e., DRAM). If the page size is 1 KB, then…

A: Assume a 32-bit virtual address and 4 MBs of memory (i.e., DRAM). If the page size is 1 KB, then…

Q: Given is : Logical Address=33bit Physical Address=24bit Page Size =2KB. System is byte addressable.…

A: Given that, Number of Logical address bits= 33 Number of Physical address bits= 24 Page size= 2 kb=…

Q: Consider a disk pack with 32 surfaces, 64 tracks and 512 sectors per pack. 256 bytes of data are…

A: Introduction  given,  A disk pack specifications. We have to calculate the number of bits to specify…

Q: 1. Consider a logical address of 128 pages of 1024 words each, mapped onto a physical memory of 64…

A: The answer as given below:

Q: 6. Consider a logical address space of 16 pages of 2048 words each, mapped onto a physical memory of…

A: Given that, Logical address of 16 pages of 2048 words each. Number of physical memory frames= 4

Q: Consider the following portion of a page table from a system with 4 KiB (i.e., 4096 byte) pages.…

A: We have given portion of page table and page size is 4KiB. Using virtual memory address, we have to…