Given a half wave rectifier wiith input voltage at the primary of 110 volts rms and turns ratio of 10:1. RL is 5 k ohms. What is the RMS voltage at the secondary? (Assume voltage drops at diodes are negligible):
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- What is the difference between a diode and rectifier?How is a solid-state diode tested? Explain.consider the figure below that shows an approximated reverse recovery turn-off characteristics for a power diode. Show that the following relation can express the total reverse recovery charge, Qrr = 1/2(trr*ts1) di1/dt =1/2(trr*ts21) di2/dt * ip Isl 1s2! -Ir
- Draw the input waveform and output waveform for the circuit given below with proper values marked in the figure. Assume D1 as germanium and D2 as silicon diodes. Input Vpp%3D20V, V1=3 V and V2=10 V. R D2 D1 Vin Vout V1 V2 Maximum voltage of output waveform Minimum voltage of output waveform PsIn the circuit shown below. Determine the following a. Vs (at the secondary) b. Vout (across RL) c. Vrip (ripple votage) d. VDC e. PIV (Peak Inverse Voltage) 10:1 Output 115 V mis 60 Hz RL 2.2 k) D, 50μF- All diodes are IN4001. Tund AlMannai EENG261 Page 5/11A silicon diode has 1 ampere DC of current in biasd mode. What is voltage drop across the diode?
- H.W4 The diode in the single-phase half wave rectifier has a reverse recovery time of t 150μsec and the source voltage V₁ 200V at frequency = 5 kHz. Calculate the average output voltage. = =In a full wave rectifier circuit involving double diodes, a sinusoidal input signal of the following nature is applied e=10 sin(500*pi*t) V. What will be value of the dc voltage obtained at the output of the rectifier.3 Given the bridge-type full-wave rectifier circuit shown 220V 60Hz 220V:Es Es D1 D2 D3 D4 The load resistor is 220 and the transformer average current is 300mA. Determine: (a) Average value, RMS value, and frequency of load voltage VRL. (b) Average current and PIV of each diode. RL
- Draw the input waveform and output waveform for the circuit given below with proper values marked in the figure. Assume D1 as silicon and D2 as germanium diodes. Input Vpp=20V. V1=5 V and V2=9 V. R www D1 Vin Vout v1 V2 Maximum voltage of output waveform Minimum voltage of output waveformA full wave bridge rectifier is supplied from 230V, 50Hz and uses a transformer of turns ration 15:1. It uses load resistance of 50 ohms. Calculate load voltage and ripple voltage. Assume ideal diode and transformer. Assume ripple factor equals to 0.482. a.Load Voltage= 13.8 V; Ripple Voltage=6.652 V b.Load Voltage= 15.6 V; Ripple Voltage=7.611 V c.Load Voltage= 21.3 V; Ripple Voltage=8.410 V d.Load Voltage= 25.1 V; Ripple Voltage=10.442 VConsider the circuit in the figure below 4:1 120 V rms ooooo gll reelee D₁ L a. What type of circuit is this? b. What is the total peak secondary voltage? D₂ c. Find the peak voltage across each half of the secondary. d. Sketch the voltage waveform across RL. e. What is the peak current through each diode? f. What is the PIV for each diode? RL 1.0 ΚΩ