Exercise 3 Compare between Half-wave and Full-wave in term of the following: a- Number of diodes b- Law of average voltage c- Diagram of the wave after rectifier
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- Can someone please provide a step by step solution? Thank you! The full wave rectifier in the circuit below is to deliver 0.25A and 15V (peak) to a load. The ripple is to be no larger than 0.4 V peak-to-peak. The input signal is 120 V (rms) at 60 Hz. Assume V(lambda) = 0.7 V . Determine the required turns ratio, the filter capacitance, and the diode PIV rating.In RL load connected (without free transition diode), single phase, uncontrolled, full wave rectifier (4 diodes), the source voltage is sinusoidal and its effective value is 44Volt, 50 Hz. The ohmic load value connected to the circuit is 10 ohms. Average value of load current calculate. (L>>R) a) 4.16 A b) 3.46 A C) 3.26A d) 4.56 A e) 3.96 AA sinusoidal signal with a maximum value of 12V is applied to the input of the bridge type rectifier circuit. Since silicon diodes with a threshold voltage of 0.7V are used in the circuit, what is the maximum voltage of the signal at the output of the rectifier?
- For the rectifier in the figure below, state the conduction sequence of the diodes for periods t1 to tó. D1 D2 D3 22) tl: D. & D.. 23) t2: D. & D.. 24) t3: D. & D.. 25) t4: D. & D.. D4 D5 D6 26) t5: D. &D. 27) t6: D.AN A & D....... Vm cot t6Determine the a.c. ripple voltage across the load of full wave rectifier which delivers 40 W to a load resistance of 150 ohm, and ripple factor is given as 1% A) 77.4 V B) 38.7 V C) 0.387 V D) 0.774 VConsider the half-wave rectifier shown below. It needs to deliver 0.1 A and an average of 15 V to a load. The source is 60 Hz and the diode has a 0.7 V drop. The allowable ripple is no more than 0.4 V (2.5%). Find: Peak AC voltage Vm of the source a) b) The minimum value of the smoothing capacitor(s) c) Comment on the type of capacitor and its/their values you would use for this amount of capacitance vs(t) K Load UL
- Consider the following circuit diagram. Using practical diode model solve the following items. i. What is the type of rectification in this circuit? ii. Calculate the total peak secondary voltage (Note that “RMS" value is given in the circuit) iii. Sketch the plot of time vs voltage over Load (RL) iv. Find the average voltage over Load. v. Find the maximum current passing over diodes. vi. Find the peak inverse voltage (PIV) over the diodes. vii. Find the minimum fuse current rating for the primary coil. 5:1 D DA 120 V rms D3 D2 RL=10kQ RL out ell lelllA bridge rectifier circuit has secondary voltage of 12 V Assume secondary resistance and diode forward resistance to be negligible. Load resistance is 100(ohm.) Calculate peak load current, DC load current, rms current and across each diode.Consider the half-wave rectifier shown in the figure below. Let vs be a sinusoidal with 10V peak amplitude with frequency of 60Hz and let R = 1000 ohms. Use the contant voltage-drop diode model with VD = 0.7 V.