generator delivers power through a transmission line at 23 kV. The resulting line loss across the 23-kV transmission line is 7.6 MW. To reduce the losses, a step-up transformer rated 23 KV/230 kV is used. What will be the new loss in MW across a 230-kV transmission line? (four decimal places)
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6. A generator delivers power through a transmission line at 23 kV. The resulting line loss across the 23-kV transmission line is 7.6 MW. To reduce the losses, a step-up transformer rated 23 KV/230 kV is used. What will be the new loss in MW across a 230-kV transmission line? (four decimal places)
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- Three single-phase, two-winding transformers, each rated 450MVA,20kV/288.7kV, with leakage reactance Xeq=0.10perunit, are connected to form a three-phase bank. The high-voltage windings are connected in Y with a solidly grounded neutral. Draw the per-unit equivalent circuit if the low-voltage windings are connected (a) in with American standard phase shift or (b) in Y with an open neutral. Use the transformer ratings as base quantities. Winding resistances and exciting current are neglected.Consider the oneline diagram shown in Figure 3.40. The three-phase transformer bank is made up of three identical single-phase transformers, each specified by X1=0.24 (on the low-voltage side), negligible resistance and magnetizing current, and turns ratio =N2/N1=10. The transformer bank is delivering 100 MW at 0.8 p.f. lagging to a substation bus whose voltage is 230 kV. (a) Determine the primary current magnitude, primary voltage (line-to-line) magnitude, and the three-phase complex power supplied by the generator. Choose the line-to-neutral voltage at the bus, Va as the reference Account for the phase shift, and assume positive-sequence operation. (b) Find the phase shift between the primary and secondary voltages.Consider the three single-phase two-winding transformers shown in Figure 3.37. The high-voltage windings are connected in Y. (a) For the low-voltage side, connect the windings in , place the polarity marks, and label the terminals a, b, and c in accordance with the American standard. (b) Relabel the terminals a, b, and c such that VAN is 90 out of phase with Va for positive sequence.
- A bank of three single-phase transformers, each rated 30MVA,38.1/3.81kV, are connected in Y- with a balanced load of three 1, Y-connected resistors. Choosing a base of 90MVA,66kV for the high-voltage side of the three-phase transformer. spify the base for the low-voltage side. Compute the per-unit resistance of the load on the base for the low-voltage side. Also, determine the load resistance in ohms referred to the high-voltage side and the per-unit value on the chosen base.A generator delivers power through a transmission line at 23 kV. The resulting line loss across the 23-kV transmission line is 4.3 MW. To reduce the losses, a step-up transformer rated 23 KV/230 kV is used. What will be the new loss in MW across a 230-kV transmission line?Two 100-kW, single-phase transformers are connected in parallel both on the primary and secondary. One transformer has an ohmic drop of 0.5% at full-load and an inductive drop of 8% at full-load current. The other has an ohmic drop of 0.75% and an inductive drop of 2%. Show how they will share a load of 180 kW at 0.9 p.f.
- What is the main direct cause of reactive power in AC system?A. Resistance of transmission linesB. Inductance and capacitance in the loadsC. Ideal transformer connected in the systemD. Power produced by generatorThe net cross section of a transformer is 20 square inches. The maximum fluxdensity is 11 kilogausses. The frequency is 60 Hz. If there are 1,000 turns in theprimary, determine the primary induced emf.The hysteresis coefficient of the core material of a power transformer is 110J/ m3. The eddy current coefficient is 132.87J/m3. The volume of the core is 0.005m3, the thickness of the iron is 0.07 m and the maximum flux density is 1.12T. If the supply frequency is 50 Hz: (a) Determine the hysteresis loss (b) Determine the eddy current loss (c) Determine the core loss of this transformer. (d) Explain how the eddy currents are generated. Suggest one method to minimise this loss. (e) Illustrate the hysteresis losses using a fully labelled hysteresis loop.
- The p.u. impedance value of an alternator corresponding to base values of 13.2 kV and 30 MVA is 0.2 p.u. Then the p.u. impedance value of an alternator for the new base values of 13.8 kV and 50 MVA is......10. In a transformer, the leakage flux of each wind- ing is proportional to the current in that winding because (a) Ohm's law applies to magnetic circuits (b) leakage paths do not saturate (c) the two windings are electrically isolated (d) mutual flux is confined to the core. 11. In a two-winding transformer, the e.m.f.per turn in secondary winding is always.........the induced e.m.f. power turn in primary. (a) equal to K times (b) equal to 1/K times (c) equal to (d) greater than. 12. In relation to a transformer, the ratio 20: 1 indi- cates that (a) there are 20 turns on primary one turn on secondary (b) secondary voltage is 1/20th of primary voltage (c) primary current is 20 times greater than the secondary current. (d) for every 20 turns on primary, there is one turn on secondary.With base MVA of 150 and base voltage of 33. If the reactance of the transformer is 0.23 pu. The parameter of the reactance of the transformer in the Neplan software is O 1.66 2.30 23 0.23 O Non of them