For the reaction 2 NO (g) +2 H2 at1100° C, the following data have been obtained. N2 (G) + 2 H,Og [NO] [H,] Rate = -A[NO]/ At ( mol/Ls) (mol/L) (mol/ L) 5.0 x 10 3 0.32 0.012 1.0 x 10 2 0.32 0.024 1.0 x 10 2 0.64 0.096 Derive a rate law for the reaction, and determine the value of the rate constant, O a Rate = k [N,[H2 Of Ob. Rate = k [No[H Oc Rate = k [NO][H,F O d. Rate = k [NO][H,] k = 23 L/ mol-s k = 23L/mol-s %3D k = 23 L2 mol2s 1 k = 23L /mol-s

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Chapter1: Chemical Foundations
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For the reaction
2 NO (G) +2 Hao-
N2 +2 H,0g
at1100 C, the following data have been obtained.
[NO]
[H,]
Rate = -A[NOj / AL
...
(mol/L)
5.0x 10 3
(mol/ L)
(mol/Ls)
.
0.32
0.012
1.0 x 10
0.32
0.024
1.0x 10 2
0.64
0.096
Derive a rate law for the reaction, and determine the value of the rate constant
Rate = k [N2][H, of
Ob Rate k (NO] [HJ
a.
k = 23 L/ mol-s
%3D
%3D
k = 23L/mol-s
Rate = k [NO] [H,]r
Od. Rate = k [NO] [H]
k-23 L mol s
k = 23L /mol-s
Transcribed Image Text:For the reaction 2 NO (G) +2 Hao- N2 +2 H,0g at1100 C, the following data have been obtained. [NO] [H,] Rate = -A[NOj / AL ... (mol/L) 5.0x 10 3 (mol/ L) (mol/Ls) . 0.32 0.012 1.0 x 10 0.32 0.024 1.0x 10 2 0.64 0.096 Derive a rate law for the reaction, and determine the value of the rate constant Rate = k [N2][H, of Ob Rate k (NO] [HJ a. k = 23 L/ mol-s %3D %3D k = 23L/mol-s Rate = k [NO] [H,]r Od. Rate = k [NO] [H] k-23 L mol s k = 23L /mol-s
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