a. From the given data, calculate the volume of the irregularly – solid and      determine the density and specific gravity of the irregularly shape – solid. Final volume of water (increase in volume)                5.30 mL Initial volume of water                                                5.00 mL        Volume of irregularly – shape solid (a –b)                  ________                                               mass of the irregularly shape – solid = 3.84 g   b.  The temperature of the water in the glass is 28.5 0 C and the boiling temperature of the water is 211.5 0 Convert the temperatures given into different temperature scale in degree Celsius scale (0C) to degree Fahrenheit (0F), Kelvin (K) and Rankine (R)   scales.                  c = 0 F - 32 / 1.8                                   0 F = 1.8  (0 C) + 32                  K = 0 C + 273.15                                       R = 0 F + 460

Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter10: Liquids And Solids
Section: Chapter Questions
Problem 2ALQ: Consider a sealed container half-filled with water. Which statement best describes what occurs in...
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a. From the given data, calculate the volume of the irregularly – solid and

     determine the density and specific gravity of the irregularly shape – solid.

  1. Final volume of water (increase in volume)                5.30 mL
  2. Initial volume of water                                                5.00 mL       
  3. Volume of irregularly – shape solid (a –b)                  ________               

                               mass of the irregularly shape – solid = 3.84 g

 

b.  The temperature of the water in the glass is 28.5 0 C and the boiling temperature of the water is 211.5 0 Convert the temperatures given into different temperature scale in degree Celsius scale (0C) to degree Fahrenheit (0F), Kelvin (K) and Rankine (R)   scales.

                 c = 0 F - 32 / 1.8                                   0 F = 1.8  (0 C) + 32

                 K = 0 C + 273.15                                       R = 0 F + 460

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